提交 1022cb6c 编写于 作者: J Jesse Brandeburg 提交者: Jeff Kirsher

i40e: do not flush after re-enabling interrupts

Hot path doesn't need read-flush after interrupt enable, and this
flush really causes a lot of extra cpu utilization.
Signed-off-by: NJesse Brandeburg <jesse.brandeburg@intel.com>
Tested-by: NKavindya Deegala <kavindya.s.deegala@intel.com>
Signed-off-by: NJeff Kirsher <jeffrey.t.kirsher@intel.com>
上级 bda301c9
......@@ -2560,7 +2560,7 @@ void i40e_irq_dynamic_enable(struct i40e_vsi *vsi, int vector)
I40E_PFINT_DYN_CTLN_CLEARPBA_MASK |
(I40E_ITR_NONE << I40E_PFINT_DYN_CTLN_ITR_INDX_SHIFT);
wr32(hw, I40E_PFINT_DYN_CTLN(vector - 1), val);
i40e_flush(hw);
/* skip the flush */
}
/**
......@@ -2709,6 +2709,7 @@ static int i40e_vsi_enable_irq(struct i40e_vsi *vsi)
i40e_irq_dynamic_enable_icr0(pf);
}
i40e_flush(&pf->hw);
return 0;
}
......
......@@ -559,8 +559,6 @@ static void i40e_update_dynamic_itr(struct i40e_q_vector *q_vector)
i40e_set_new_dynamic_itr(&q_vector->tx);
if (old_itr != q_vector->tx.itr)
wr32(hw, reg_addr, q_vector->tx.itr);
i40e_flush(hw);
}
/**
......
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