提交 02bf60aa 编写于 作者: A Anton Blanchard 提交者: Arnaldo Carvalho de Melo

perf: Fix performance issue with perf report

On a large machine we spend a lot of time in perf_header__find_attr when
running perf report.

If we are parsing a file without PERF_SAMPLE_ID then for each sample we call
perf_header__find_attr and loop through all counter IDs, never finding a match.
As the machine gets larger there are more per cpu counters and we spend an
awful lot of time in there.

The patch below initialises each sample id to -1ULL and checks for this in
perf_header__find_attr. We may need to do something more intelligent eventually
(eg a hash lookup from counter id to attr) but this at least fixes the most
common usage of perf report.

Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Paul Mackerras <paulus@samba.org>
Cc: Ingo Molnar <mingo@elte.hu>
Cc: Frederic Weisbecker <fweisbec@gmail.com>
Cc: Eric B Munson <ebmunson@us.ibm.com>
Acked-by: NEric B Munson <ebmunson@us.ibm.com>
LKML-Reference: <20100504111915.GB14636@kryten>
Signed-off-by: NAnton Blanchard <anton@samba.org>
--
Signed-off-by: NArnaldo Carvalho de Melo <acme@redhat.com>
上级 11d232ec
...@@ -713,6 +713,7 @@ int event__parse_sample(event_t *event, u64 type, struct sample_data *data) ...@@ -713,6 +713,7 @@ int event__parse_sample(event_t *event, u64 type, struct sample_data *data)
array++; array++;
} }
data->id = -1ULL;
if (type & PERF_SAMPLE_ID) { if (type & PERF_SAMPLE_ID) {
data->id = *array; data->id = *array;
array++; array++;
......
...@@ -922,6 +922,14 @@ perf_header__find_attr(u64 id, struct perf_header *header) ...@@ -922,6 +922,14 @@ perf_header__find_attr(u64 id, struct perf_header *header)
{ {
int i; int i;
/*
* We set id to -1 if the data file doesn't contain sample
* ids. Check for this and avoid walking through the entire
* list of ids which may be large.
*/
if (id == -1ULL)
return NULL;
for (i = 0; i < header->attrs; i++) { for (i = 0; i < header->attrs; i++) {
struct perf_header_attr *attr = header->attr[i]; struct perf_header_attr *attr = header->attr[i];
int j; int j;
......
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