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由 Oleg Nesterov 提交于
Change queue_delayed_work() to use queue_delayed_work_on() to avoid the code duplication (saves 133 bytes). Q: queue_delayed_work() enqueues &dwork->work directly when delay == 0, why? [jirislaby@gmail.com: oops fix] Signed-off-by: NOleg Nesterov <oleg@tv-sign.ru> Signed-off-by: NJiri Slaby <jirislaby@gmail.com> Signed-off-by: NAndrew Morton <akpm@linux-foundation.org> Signed-off-by: NLinus Torvalds <torvalds@linux-foundation.org>
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