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未验证 提交 92b8cf97 编写于 作者: M MountainOne 提交者： GitHub
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[ISSUE #1505]Fix the ListSplitter of batch sample in docs

上级 30ad1723
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Showing with 78 addition and 69 deletion
docs/cn/RocketMQ_Example.md
浏览文件 @ 92b8cf97
......@@ -500,48 +500,52 @@ try {
复杂度只有当你发送大批量时才会增长，你可能不确定它是否超过了大小限制（4MB）。这时候你最好把你的消息列表分割一下：
```java
public class ListSplitter implements Iterator<List<Message>> {
private final int SIZE_LIMIT = 1024 * 1024 * 4;
private final List<Message> messages;
private int currIndex;
public ListSplitter(List<Message> messages) {
this.messages = messages;
}
@Override public boolean hasNext() {
return currIndex < messages.size();
}
@Override public List<Message> next() {
int nextIndex = currIndex;
int totalSize = 0;
for (; nextIndex < messages.size(); nextIndex++) {
Message message = messages.get(nextIndex);
int tmpSize = message.getTopic().length() + message.getBody().length;
Map<String, String> properties = message.getProperties();
for (Map.Entry<String, String> entry : properties.entrySet()) {
tmpSize += entry.getKey().length() + entry.getValue().length();
}
tmpSize = tmpSize + 20; // 增加日志的开销20字节
if (tmpSize > SIZE_LIMIT) {
//单个消息超过了最大的限制
//忽略,否则会阻塞分裂的进程
if (nextIndex - currIndex == 0) {
//假如下一个子列表没有元素,则添加这个子列表然后退出循环,否则只是退出循环
nextIndex++;
}
break;
}
if (tmpSize + totalSize > SIZE_LIMIT) {
break;
} else {
totalSize += tmpSize;
}
}
List<Message> subList = messages.subList(currIndex, nextIndex);
currIndex = nextIndex;
return subList;
}
public class ListSplitter implements Iterator<List<Message>> {
private final int SIZE_LIMIT = 1024 * 1024 * 4;
private final List<Message> messages;
private int currIndex;
public ListSplitter(List<Message> messages) {
this.messages = messages;
}
@Override public boolean hasNext() {
return currIndex < messages.size();
}
@Override public List<Message> next() {
int startIndex = getStartIndex();
int nextIndex = startIndex;
int totalSize = 0;
for (; nextIndex < messages.size(); nextIndex++) {
Message message = messages.get(nextIndex);
int tmpSize = calcMessageSize(message);
if (tmpSize + totalSize > SIZE_LIMIT) {
break;
} else {
totalSize += tmpSize;
}
}
List<Message> subList = messages.subList(startIndex, nextIndex);
currIndex = nextIndex;
return subList;
}
private int getStartIndex() {
Message currMessage = messages.get(currIndex);
int tmpSize = calcMessageSize(currMessage);
while(tmpSize > SIZE_LIMIT) {
currIndex += 1;
Message message = messages.get(curIndex);
tmpSize = calcMessageSize(message);
}
return currIndex;
}
private int calcMessageSize(Message message) {
int tmpSize = message.getTopic().length() + message.getBody().length();
Map<String, String> properties = message.getProperties();
for (Map.Entry<String, String> entry : properties.entrySet()) {
tmpSize += entry.getKey().length() + entry.getValue().length();
}
tmpSize = tmpSize + 20; // 增加⽇日志的开销20字节
return tmpSize;
}
}
//把大的消息分裂成若干个小的消息
ListSplitter splitter = new ListSplitter(messages);
......
docs/en/Example_Batch.md
浏览文件 @ 92b8cf97
......@@ -19,47 +19,52 @@ try {
### 2 Split into Lists
The complexity only grow when you send large batch and you may not sure if it exceeds the size limit (4MiB). At this time, you’d better split the lists:
```java
public class ListSplitter implements Iterator<List<Message>> {
private final int SIZE_LIMIT = 1000 * 1000;
public class ListSplitter implements Iterator<List<Message>> {
private final int SIZE_LIMIT = 1024 * 1024 * 4;
private final List<Message> messages;
private int currIndex;
public ListSplitter(List<Message> messages) {
this.messages = messages;
public ListSplitter(List<Message> messages) {
this.messages = messages;
}
@Override public boolean hasNext() {
return currIndex < messages.size();
return currIndex < messages.size();
}
@Override public List<Message> next() {
int nextIndex = currIndex;
@Override public List<Message> next() {
int startIndex = getStartIndex();
int nextIndex = startIndex;
int totalSize = 0;
for (; nextIndex < messages.size(); nextIndex++) {
Message message = messages.get(nextIndex);
int tmpSize = message.getTopic().length() + message.getBody().length;
Map<String, String> properties = message.getProperties();
for (Map.Entry<String, String> entry : properties.entrySet()) {
tmpSize += entry.getKey().length() + entry.getValue().length();
}
tmpSize = tmpSize + 20; //for log overhead
if (tmpSize > SIZE_LIMIT) {
//it is unexpected that single message exceeds the SIZE_LIMIT
//here just let it go, otherwise it will block the splitting process
if (nextIndex - currIndex == 0) {
//if the next sublist has no element, add this one and then break, otherwise just break
nextIndex++;
}
break;
}
Message message = messages.get(nextIndex);
int tmpSize = calcMessageSize(message);
if (tmpSize + totalSize > SIZE_LIMIT) {
break;
break;
} else {
totalSize += tmpSize;
totalSize += tmpSize;
}
}
List<Message> subList = messages.subList(currIndex, nextIndex);
List<Message> subList = messages.subList(startIndex, nextIndex);
currIndex = nextIndex;
return subList;
}
private int getStartIndex() {
Message currMessage = messages.get(currIndex);
int tmpSize = calcMessageSize(currMessage);
while(tmpSize > SIZE_LIMIT) {
currIndex += 1;
Message message = messages.get(curIndex);
tmpSize = calcMessageSize(message);
}
return currIndex;
}
private int calcMessageSize(Message message) {
int tmpSize = message.getTopic().length() + message.getBody().length();
Map<String, String> properties = message.getProperties();
for (Map.Entry<String, String> entry : properties.entrySet()) {
tmpSize += entry.getKey().length() + entry.getValue().length();
}
tmpSize = tmpSize + 20; // Increase the log overhead by 20 bytes
return tmpSize;
}
}
// then you could split the large list into small ones:
......
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