t0020: fix ignored exit code inside loops
A loop like: for f in one two; do something $f || break done will correctly break out of the loop when we see a failure of one item, but the resulting exit code will always be zero. We can fix that by putting the loop into a function or subshell, but in this case it is simpler still to just unroll the loop. We do add a helper function, which hopefully makes the end result even more readable (in addition to being shorter). Reported-by: NSZEDER Gábor <szeder@ira.uka.de> Signed-off-by: NJeff King <peff@peff.net> Signed-off-by: NJunio C Hamano <gitster@pobox.com>
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