提交 d37dc239 编写于 作者: M Matthew DeVore 提交者: Junio C Hamano

url: do not allow %00 to represent NUL in URLs

There is no reason to allow %00 to terminate a string, so do not allow it.
Otherwise, we end up returning arbitrary content in the string (that which is
after the %00) which is effectively hidden from callers and can escape sanity
checks and validation, and possible be used in tandem with a security
vulnerability to introduce a payload.
Helped-by: Nbrian m. carlson <sandals@crustytoothpaste.net>
Signed-off-by: NMatthew DeVore <matvore@google.com>
Signed-off-by: NJunio C Hamano <gitster@pobox.com>
上级 3f6b8a61
......@@ -48,7 +48,7 @@ static char *url_decode_internal(const char **query, int len,
if (c == '%' && (len < 0 || len >= 3)) {
int val = hex2chr(q + 1);
if (0 <= val) {
if (0 < val) {
strbuf_addch(out, val);
q += 3;
len -= 3;
......
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