提交 9fa2e5e8 编写于 作者: B Brandon Williams 提交者: Junio C Hamano

remote: convert match_explicit_refs to take a struct refspec

Convert 'match_explicit_refs()' to take a 'struct refspec' as a
parameter instead of a list of 'struct refspec_item'.
Signed-off-by: NBrandon Williams <bmwill@google.com>
Signed-off-by: NJunio C Hamano <gitster@pobox.com>
上级 f3acb830
......@@ -1073,12 +1073,11 @@ static int match_explicit(struct ref *src, struct ref *dst,
}
static int match_explicit_refs(struct ref *src, struct ref *dst,
struct ref ***dst_tail, struct refspec_item *rs,
int rs_nr)
struct ref ***dst_tail, struct refspec *rs)
{
int i, errs;
for (i = errs = 0; i < rs_nr; i++)
errs += match_explicit(src, dst, dst_tail, &rs[i]);
for (i = errs = 0; i < rs->nr; i++)
errs += match_explicit(src, dst, dst_tail, &rs->items[i]);
return errs;
}
......@@ -1302,7 +1301,7 @@ int match_push_refs(struct ref *src, struct ref **dst,
refspec = default_refspec;
}
refspec_appendn(&rs, refspec, nr_refspec);
errs = match_explicit_refs(src, *dst, &dst_tail, rs.items, rs.nr);
errs = match_explicit_refs(src, *dst, &dst_tail, &rs);
/* pick the remainder */
for (ref = src; ref; ref = ref->next) {
......
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