rev-list: estimate number of bisection step left
This patch teaches "git rev-list --bisect-vars" to output an estimate of the number of bisection step left _after the current one_ along with the other variables it already outputs. This patch also makes "git-bisect.sh" display this number of steps left _after the current one_, along with the estimate of the number of revisions left to test (after the current one). Here is a table to help analyse what should be the best estimate for the number of bisect steps left. N : linear case --> probabilities --> best ------------------------------------------------------------- 1 : G-B --> 0 --> 0 2 : G-U1-B --> 0 --> 0 3 : G-U1-U2-B --> 0(1/3) 1(2/3) --> 1 4 : G-U1-U2-U3-B --> 1 --> 1 5 : G-U1-U2-U3-U4-B --> 1(3/5) 2(2/5) --> 1 6 : G-U1-U2-U3-U4-U5-B --> 1(2/6) 2(4/6) --> 2 7 : G-U1-U2-U3-U4-U5-U6-B --> 1(1/7) 2(6/7) --> 2 8 : G-U1-U2-U3-U4-U5-U6-U7-B --> 2 --> 2 9 : G-U1-U2-U3-U4-U5-U6-U7-U8-B --> 2(7/9) 3(2/9) --> 2 10: G-U1-U2-U3-U4-U5-U6-U7-U8-U9-B --> 2(6/10)3(4/10)--> 2 In the column "N", there is the number of revisions that could _now_ be the first bad commit we are looking for. The "linear case" column describes the linear history corresponding to the number in column N. G means good, B means bad, and Ux means unknown. Note that the first bad revision we are looking for can be any Ux or B. In the "probabilities" column, there are the different outcomes in number of steps with the odds of each outcome in parenthesis corresponding to the linear case. The "best" column gives the most accurate estimate among the different outcomes in the "probabilities" column. We have the following: best(2^n) == n - 1 and for any x between 0 included and 2^n excluded, the probability for n - 1 steps left looks like: P(2^n + x) == (2^n - x) / (2^n + x) and P(2^n + x) < 0.5 means 2^n < 3x So the algorithm used in this patch calculates 2^n and x, and then choose between returning n - 1 and n. Signed-off-by: NChristian Couder <chriscool@tuxfamily.org> Signed-off-by: NJunio C Hamano <gitster@pobox.com>
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