-
由 René Scharfe 提交于
The result of st_mult() is the same no matter the order of its arguments. It invokes the macro unsigned_mult_overflows(), which divides the second parameter by the first one. Pass constants first to allow that division to be done already at compile time. Signed-off-by: NRene Scharfe <l.s.r@web.de> Reviewed-by: NJeff King <peff@peff.net> Signed-off-by: NJunio C Hamano <gitster@pobox.com>
50492f7b