-
由 Patrick Walton 提交于
of `use bar as foo`. Change all uses of `use foo = bar` to `use bar as foo`. Implements RFC #47. Closes #16461. [breaking-change]
67deb2e6
of `use bar as foo`. Change all uses of `use foo = bar` to `use bar as foo`. Implements RFC #47. Closes #16461. [breaking-change]