列表推导式第一次提交

列表推导式/题目1.py

+"""
+以下哪个列表推导式能实现与下述 `for` 循环一样的效果？
+
+```python
+my_numbers = [3, 1, 5, 2, 4]
+result = []
+for i in range(len(my_numbers)):
+    result.append(my_numbers[i] ** 2)
+
+print(result)
+```
+"""
+
+print([i ** 2 for i in [3, 1, 5, 2, 4]])

列表推导式/题目2.py

+"""
+请选出能将下述列表中每一项都扩大一倍的列表推导式
+
+```python
+[1,2,3,4,5,6,7,8,9,10]
+```
+"""
+
+my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
+print([i * 2 for i in my_list])

列表推导式/题目3.py

+"""
+请选择出与下述代码等价的列表推导式代码
+
+```python
+result = []
+for x in range(1, 5):
+	for y in range(6, 10):
+		result.append((x, y))
+
+print(result)
+```
+"""
+
+print([(x, y) for x in range(1, 5) for y in range(6, 10)])

列表推导式/题目4.py

+"""
+请使用列表推导式筛选出下述列表中 3 或者 7 的倍数。
+
+```python
+my_list = list(range(1,100))
+```
+"""
+my_list = list(range(1, 100))
+print([i for i in my_list if i % 3 == 0 or i % 7 == 0])

列表推导式/题目5.py

+"""
+通过列表推导式，删除下述列表中的重复元素。
+
+```python
+my_list = [1, 1, 2, 2, 2, 3, 3, 3, 4, 4]
+```
+"""
+
+my_list = [1, 1, 2, 2, 2, 3, 3, 3, 4, 4]
+ret = []
+temp = [ret.append(i) for i in my_list if i not in ret]
+print(ret)

列表推导式/题目6.py

+"""
+通过列表推导式，将下述大列表拆分成小列表
+
+```python
+my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
+# 如每组3个元素，预期结果 [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
+```
+
+"""
+my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
+# 不做非数字验证
+item_count = int(input("请输入子列表元素数："))
+temp = [my_list[i:i + item_count] for i in range(0, len(my_list), item_count)]
+print(temp)