提交 5a38b6e6 编写于 作者: I Igor Mammedov 提交者: Paolo Bonzini

kvm: update_memslots: drop not needed check for the same number of pages

if number of pages haven't changed sorting algorithm
will do nothing, so there is no need to do extra check
to avoid entering sorting logic.
Signed-off-by: NIgor Mammedov <imammedo@redhat.com>
Signed-off-by: NPaolo Bonzini <pbonzini@redhat.com>
上级 45c3094a
......@@ -679,21 +679,19 @@ static void update_memslots(struct kvm_memslots *slots,
struct kvm_memory_slot *mslots = slots->memslots;
WARN_ON(mslots[i].id != id);
if (new->npages != mslots[i].npages) {
if (new->npages < mslots[i].npages) {
while (i < KVM_MEM_SLOTS_NUM - 1 &&
new->npages < mslots[i + 1].npages) {
mslots[i] = mslots[i + 1];
slots->id_to_index[mslots[i].id] = i;
i++;
}
} else {
while (i > 0 &&
new->npages > mslots[i - 1].npages) {
mslots[i] = mslots[i - 1];
slots->id_to_index[mslots[i].id] = i;
i--;
}
if (new->npages < mslots[i].npages) {
while (i < KVM_MEM_SLOTS_NUM - 1 &&
new->npages < mslots[i + 1].npages) {
mslots[i] = mslots[i + 1];
slots->id_to_index[mslots[i].id] = i;
i++;
}
} else {
while (i > 0 &&
new->npages > mslots[i - 1].npages) {
mslots[i] = mslots[i - 1];
slots->id_to_index[mslots[i].id] = i;
i--;
}
}
......
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