1. 04 9月, 2013 1 次提交
  2. 28 8月, 2013 2 次提交
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  10. 07 8月, 2013 1 次提交
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  13. 01 8月, 2013 1 次提交
  14. 31 7月, 2013 1 次提交
  15. 30 7月, 2013 2 次提交
  16. 26 7月, 2013 2 次提交
  17. 22 7月, 2013 1 次提交
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  20. 17 7月, 2013 2 次提交
  21. 10 7月, 2013 2 次提交
  22. 03 7月, 2013 1 次提交
    • H
      Bugfix for an overlapping size of image and template for matchTemplate. · a26c4fa2
      Heinz Hofbauer 提交于
      Example: img of size 10x10 and templ of size 11x9.
      In subsequent code this will results in either width or height of
      corrSize to be zero (0).
      Line 261 will call crossCorr which will then have a zero size of either
      blocksize.width or blocksize.height resulting in a division by zero
      crach in lines 137 or 138.
      a26c4fa2
  23. 26 6月, 2013 1 次提交
  24. 14 6月, 2013 1 次提交
  25. 31 5月, 2013 2 次提交
  26. 25 5月, 2013 2 次提交
  27. 13 5月, 2013 1 次提交
  28. 26 4月, 2013 1 次提交
    • R
      Changed convexHull's documentation to essentially invert the meaning of ``clockwise``. · 2dc86425
      Roman Donchenko 提交于
      The orientation of convexHull's result is currently the opposite of what the
      documentation would suggest:
      
      >>> import cv2, numpy as np
      >>> points = np.array([[0,0],[0,1],[1,0]], dtype=np.int32)
      >>> cv2.convexHull(points, clockwise=False)
      array([[[1, 0]],
             [[0, 1]],
             [[0, 0]]], dtype=int32)
      >>> cv2.convexHull(points, clockwise=True)
      array([[[0, 0]],
             [[0, 1]],
             [[1, 0]]], dtype=int32)
      
      Changing the function itself is probably not a good idea at this point, so
      this fixes the documentation by flipping the coordinate system.
      
      I also removed the mention of the origin, since it's irrelevant for this
      function.
      2dc86425
  29. 15 4月, 2013 1 次提交