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0a801354
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体验新版 GitCode,发现更多精彩内容 >>
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0a801354
编写于
12月 14, 2018
作者:
A
Alexander Alekhin
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Merge pull request #13438 from madan-ram:patch-2
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d99a4af2
c1e9a7ee
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doc/tutorials/imgproc/histograms/template_matching/template_matching.markdown
...c/histograms/template_matching/template_matching.markdown
+7
-7
未找到文件。
doc/tutorials/imgproc/histograms/template_matching/template_matching.markdown
浏览文件 @
0a801354
...
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@@ -65,7 +65,7 @@ that should be used to find the match.
-# **Mask image (M):** The mask, a grayscale image that masks the template
-
Only two matching methods currently accept a mask:
CV_TM_SQDIFF and CV_
TM_CCORR_NORMED (see
-
Only two matching methods currently accept a mask:
TM_SQDIFF and
TM_CCORR_NORMED (see
below for explanation of all the matching methods available in opencv).
...
...
@@ -86,23 +86,23 @@ that should be used to find the match.
Good question. OpenCV implements Template matching in the function
**matchTemplate()**
. The
available methods are 6:
-#
**method=
CV_
TM_SQDIFF**
-#
**method=TM_SQDIFF**
\f[R(x,y)= \sum _{x',y'} (T(x',y')-I(x+x',y+y'))^2\f]
-#
**method=
CV_
TM_SQDIFF_NORMED**
-#
**method=TM_SQDIFF_NORMED**
\f[R(x,y)= \frac{\sum_{x',y'} (T(x',y')-I(x+x',y+y'))^2}{\sqrt{\sum_{x',y'}T(x',y')^2 \cdot \sum_{x',y'} I(x+x',y+y')^2}}\f]
-#
**method=
CV_
TM_CCORR**
-#
**method=TM_CCORR**
\f[R(x,y)= \sum _{x',y'} (T(x',y') \cdot I(x+x',y+y'))\f]
-#
**method=
CV_
TM_CCORR_NORMED**
-#
**method=TM_CCORR_NORMED**
\f[R(x,y)= \frac{\sum_{x',y'} (T(x',y') \cdot I(x+x',y+y'))}{\sqrt{\sum_{x',y'}T(x',y')^2 \cdot \sum_{x',y'} I(x+x',y+y')^2}}\f]
-#
**method=
CV_
TM_CCOEFF**
-#
**method=TM_CCOEFF**
\f[R(x,y)= \sum _{x',y'} (T'(x',y') \cdot I'(x+x',y+y'))\f]
...
...
@@ -110,7 +110,7 @@ available methods are 6:
\f[\begin{array}{l} T'(x',y')=T(x',y') - 1/(w \cdot h) \cdot \sum _{x'',y''} T(x'',y'') \\ I'(x+x',y+y')=I(x+x',y+y') - 1/(w \cdot h) \cdot \sum _{x'',y''} I(x+x'',y+y'') \end{array}\f]
-#
**method=
CV_
TM_CCOEFF_NORMED**
-#
**method=TM_CCOEFF_NORMED**
\f[R(x,y)= \frac{ \sum_{x',y'} (T'(x',y') \cdot I'(x+x',y+y')) }{ \sqrt{\sum_{x',y'}T'(x',y')^2 \cdot \sum_{x',y'} I'(x+x',y+y')^2} }\f]
...
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