提交 d9b99b4b 编写于 作者: T Tom Lane

Fix erroneous parsing of tsquery input "... & !(subexpression) | ..."

After parsing a parenthesized subexpression, we must pop all pending
ANDs and NOTs off the stack, just like the case for a simple operand.
Per bug #5793.

Also fix clones of this routine in contrib/intarray and contrib/ltree,
where input of types query_int and ltxtquery had the same problem.

Back-patch to all supported versions.
上级 b16a1849
......@@ -189,8 +189,8 @@ makepol(WORKSTATE * state)
case OPEN:
if (makepol(state) == ERR)
return ERR;
if (lenstack && (stack[lenstack - 1] == (int4) '&' ||
stack[lenstack - 1] == (int4) '!'))
while (lenstack && (stack[lenstack - 1] == (int4) '&' ||
stack[lenstack - 1] == (int4) '!'))
{
lenstack--;
pushquery(state, OPR, stack[lenstack]);
......
......@@ -234,8 +234,8 @@ makepol(QPRS_STATE * state)
case OPEN:
if (makepol(state) == ERR)
return ERR;
if (lenstack && (stack[lenstack - 1] == (int4) '&' ||
stack[lenstack - 1] == (int4) '!'))
while (lenstack && (stack[lenstack - 1] == (int4) '&' ||
stack[lenstack - 1] == (int4) '!'))
{
lenstack--;
pushquery(state, OPR, stack[lenstack], 0, 0, 0);
......
......@@ -360,8 +360,8 @@ makepol(TSQueryParserState state,
case PT_OPEN:
makepol(state, pushval, opaque);
if (lenstack && (opstack[lenstack - 1] == OP_AND ||
opstack[lenstack - 1] == OP_NOT))
while (lenstack && (opstack[lenstack - 1] == OP_AND ||
opstack[lenstack - 1] == OP_NOT))
{
lenstack--;
pushOperator(state, opstack[lenstack]);
......
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