提交 ce3d1a4f 编写于 作者: T Tom Lane

Un-break ecpg regression test.

上级 34036c86
......@@ -47,7 +47,8 @@ char *dates[] = { "19990108foobar",
"January 8, 99 BC",
NULL };
char *times[] = { "0:04",
/* do not conflict with libc "times" symbol */
static char *times[] = { "0:04",
"1:59 PDT",
"13:24:40 -8:00",
"13:24:40.495+3",
......@@ -72,22 +73,22 @@ main(void)
#line 51 "dt_test2.pgc"
#line 52 "dt_test2.pgc"
date date1 ;
#line 52 "dt_test2.pgc"
#line 53 "dt_test2.pgc"
timestamp ts1 , ts2 ;
#line 53 "dt_test2.pgc"
#line 54 "dt_test2.pgc"
char * text ;
#line 54 "dt_test2.pgc"
#line 55 "dt_test2.pgc"
interval * i1 ;
#line 55 "dt_test2.pgc"
#line 56 "dt_test2.pgc"
date * dc ;
/* exec sql end declare section */
#line 56 "dt_test2.pgc"
#line 57 "dt_test2.pgc"
int i, j;
......
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