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提交 1077cdcd 编写于 作者: H Heikki Linnakangas
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Clean up 'percentile' regression test. 

Reformat some of the test queries, and make sure the formatting is the same
between the .sql file and .out file (pg_regress uses "diff -w", which masks
out some of the differences, but it was annoying while doing a manual diff).
上级 b2d28285
隐藏空白更改
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Showing with 60 addition and 52 deletion
src/test/regress/expected/percentile.out
浏览文件 @ 1077cdcd
......@@ -2,6 +2,8 @@ create table perct as select a, a / 10 as b from generate_series(1, 100)a;
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column(s) named 'a' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
create table perct2 as select a, a / 10 as b from generate_series(1, 100)a, generate_series(1, 2);
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column(s) named 'a' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
create table perct3 as select a, b from perct, generate_series(1, 10)i where a % 7 < i;
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column(s) named 'a' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
......@@ -25,8 +27,12 @@ WITH (APPENDONLY=true, COMPRESSLEVEL=5, ORIENTATION=column, COMPRESSTYPE=zlib, O
DISTRIBUTED BY (dkey_a);
insert into mpp_22219 select i, i, i from (select * from generate_series(1, 20) i ) a ;
create table mpp_21026 ( t1 varchar(10), t2 int);
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 't1' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
insert into mpp_21026 select i, i from (select * from generate_series(1, 20) i ) a ;
create table mpp_20076 (col1 timestamp, col2 int);
NOTICE: Table doesn't have 'DISTRIBUTED BY' clause -- Using column named 'col1' as the Greenplum Database data distribution key for this table.
HINT: The 'DISTRIBUTED BY' clause determines the distribution of data. Make sure column(s) chosen are the optimal data distribution key to minimize skew.
insert into mpp_20076 select to_timestamp(i),i from generate_series(1,20) i;
CREATE TABLE mpp_22413
(
......@@ -231,8 +237,8 @@ select b, count(*), count(distinct a), median(a) from perct3 group by b order by
(11 rows)
select b+1, count(*), count(distinct a),
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
?column? | count | count | median | percentile_cont
----------+-------+-------+--------+-----------------
1 | 9 | 9 | 5 | 6.6
......@@ -308,8 +314,9 @@ select percentile_disc(0) within group (order by a) from perct;
1
(1 row)
prepare p (float) as select percentile_cont($1) within group (order by a)
from perct group by b order by b;
prepare p (float) as
select percentile_cont($1) within group (order by a)
from perct group by b order by b;
execute p(0.1);
percentile_cont
-----------------
......@@ -356,7 +363,7 @@ select percentile_cont(null) within group (order by a) from perct;
(1 row)
select percentile_cont(null) within group (order by a),
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_cont | percentile_disc
-----------------+-----------------
|
......@@ -373,11 +380,11 @@ select percentile_cont(null) within group (order by a),
(11 rows)
select median(a), percentile_cont(0.5) within group (order by a),
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
median | percentile_cont | percentile_disc | ?column? | ?column?
--------------------------+--------------------------+--------------------------+--------------------------+--------------------------
Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012
......@@ -401,14 +408,14 @@ select percentile_cont(1.0/86400) within group (order by a) from percts
(1 row)
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont | percentile_cont
--------------------------+--------------------------
Wed Jan 11 21:36:00 2012 | Wed Jan 11 21:36:00 2012
(1 row)
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont | percentile_cont
------------------------------+------------------------------
Wed Jan 11 13:36:00 2012 PST | Sat Jan 21 11:12:00 2012 PST
......@@ -694,8 +701,8 @@ select b, count(*), count(distinct a), median(a) from perct3 group by b order by
(11 rows)
select b+1, count(*), count(distinct a),
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
?column? | count | count | median | percentile_cont
----------+-------+-------+--------+-----------------
1 | 9 | 9 | 5 | 6.6
......@@ -772,7 +779,7 @@ select percentile_disc(0) within group (order by a) from perct;
(1 row)
prepare p (float) as select percentile_cont($1) within group (order by a)
from perct group by b order by b;
from perct group by b order by b;
execute p(0.1);
percentile_cont
-----------------
......@@ -819,7 +826,7 @@ select percentile_cont(null) within group (order by a) from perct;
(1 row)
select percentile_cont(null) within group (order by a),
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_cont | percentile_disc
-----------------+-----------------
|
......@@ -836,11 +843,11 @@ select percentile_cont(null) within group (order by a),
(11 rows)
select median(a), percentile_cont(0.5) within group (order by a),
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
median | percentile_cont | percentile_disc | ?column? | ?column?
--------------------------+--------------------------+--------------------------+--------------------------+--------------------------
Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012 | Fri Jan 06 00:00:00 2012
......@@ -864,14 +871,14 @@ select percentile_cont(1.0/86400) within group (order by a) from percts
(1 row)
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont | percentile_cont
--------------------------+--------------------------
Wed Jan 11 21:36:00 2012 | Wed Jan 11 21:36:00 2012
(1 row)
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont | percentile_cont
------------------------------+------------------------------
Wed Jan 11 13:36:00 2012 PST | Sat Jan 21 11:12:00 2012 PST
......@@ -972,9 +979,9 @@ select * from percv;
reset gp_idf_deduplicate;
select pg_get_viewdef('percv');
pg_get_viewdef
pg_get_viewdef
-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
SELECT percentile_cont(float8(0.4)) WITHIN GROUP (ORDER BY float8((perct.a / 10))) AS "percentile_cont", median(float8(perct.a)) AS "median", percentile_disc(float8(0.51)) WITHIN GROUP (ORDER BY float8(perct.a) DESC) AS "percentile_disc" FROM perct GROUP BY perct.b ORDER BY perct.b;
SELECT percentile_cont(float8(0.4)) WITHIN GROUP (ORDER BY float8((perct.a / 10))) AS "percentile_cont", median(float8(perct.a)) AS "median", percentile_disc(float8(0.51)) WITHIN GROUP (ORDER BY float8(perct.a) DESC) AS "percentile_disc" FROM perct GROUP BY perct.b ORDER BY perct.b;
(1 row)
select pg_get_viewdef('percv2');
......@@ -1051,10 +1058,10 @@ LINE 1: select percentile_cont(random()) within group (order by a) f...
-- out of range
select percentile_cont(-0.1) within group (order by a) from perct;
ERROR: input is out of range
HINT: argument to percentile function must be between 0.0 and 1.0.
HINT: Argument to percentile function must be between 0.0 and 1.0.
select percentile_cont(1.00000001) within group (order by a) from perct;
ERROR: input is out of range
HINT: argument to percentile function must be between 0.0 and 1.0.
HINT: Argument to percentile function must be between 0.0 and 1.0.
-- CSQ is not supported currently. Shame.
select sum((select median(a) from perct where b = t.b)) from perct t;
ERROR: correlated subquery cannot contain percentile functions
......@@ -1067,7 +1074,7 @@ LINE 1: select * from perct limit median(a);
select percentile_cont(0.8) within group (order by a, a + 1, a + 2) from perct;
ERROR: function "percentile_cont(double precision)" cannot accept more than one expression in ORDER BY
LINE 1: select percentile_cont(0.8) within group (order by a, a + 1,...
^
^
-- set-returning
select generate_series(1, 2), median(a) from perct;
ERROR: set-valued function called in context that cannot accept a set
......@@ -1095,7 +1102,7 @@ select (select a from perct where median(t.a) = 5) from perct t;
ERROR: percentile functions cannot reference columns from outer queries
LINE 1: select (select a from perct where median(t.a) = 5) from perc...
^
-- MPP-22219
-- MPP-22219
select count(*) from
(SELECT b.dkey_a, MEDIAN(B.VALUE)
FROM mpp_22219 B
......
src/test/regress/sql/percentile.sql
浏览文件 @ 1077cdcd
......@@ -63,34 +63,35 @@ select median(a) from perct2;
select median(a) from perct2 group by b order by b;
select b, count(*), count(distinct a), median(a) from perct3 group by b order by b;
select b+1, count(*), count(distinct a),
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
select median(a), median(c) from perct4;
select median(a), median(c) from perct4 group by b;
select count(*) over (partition by b), median(a) from perct group by b order by b;
select sum(median(a)) over (partition by b) from perct group by b order by b;
select percentile_disc(0) within group (order by a) from perct;
prepare p (float) as select percentile_cont($1) within group (order by a)
from perct group by b order by b;
prepare p (float) as
select percentile_cont($1) within group (order by a)
from perct group by b order by b;
execute p(0.1);
execute p(0.8);
deallocate p;
select sum((select median(a) from perct)) from perct;
select percentile_cont(null) within group (order by a) from perct;
select percentile_cont(null) within group (order by a),
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_disc(null) within group (order by a desc) from perct group by b;
select median(a), percentile_cont(0.5) within group (order by a),
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
select percentile_cont(1.0/86400) within group (order by a) from percts
where c between 1 and 2;
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont(0.9) within group (order by a desc) from percts;
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont(0.2) within group (order by a) from perctsz;
select median(a - (select min(a) from percts)) from percts;
select median(a), b from perct group by b order by b desc;
select count(*) from(select median(a) from perct group by ())s;
......@@ -129,34 +130,34 @@ select median(a) from perct2;
select median(a) from perct2 group by b order by b;
select b, count(*), count(distinct a), median(a) from perct3 group by b order by b;
select b+1, count(*), count(distinct a),
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
median(a), percentile_cont(0.3) within group (order by a desc)
from perct group by b+1 order by b+1;
select median(a), median(c) from perct4;
select median(a), median(c) from perct4 group by b;
select count(*) over (partition by b), median(a) from perct group by b order by b;
select sum(median(a)) over (partition by b) from perct group by b order by b;
select percentile_disc(0) within group (order by a) from perct;
prepare p (float) as select percentile_cont($1) within group (order by a)
from perct group by b order by b;
from perct group by b order by b;
execute p(0.1);
execute p(0.8);
deallocate p;
select sum((select median(a) from perct)) from perct;
select percentile_cont(null) within group (order by a) from perct;
select percentile_cont(null) within group (order by a),
percentile_disc(null) within group (order by a desc) from perct group by b;
percentile_disc(null) within group (order by a desc) from perct group by b;
select median(a), percentile_cont(0.5) within group (order by a),
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
percentile_disc(0.5) within group(order by a),
(select min(a) from percts) - interval '1day' + interval '1day' * median(c),
(select min(a) from percts) - interval '1day' + interval '1day' *
percentile_disc(0.5) within group (order by c)
from percts group by b order by b;
select percentile_cont(1.0/86400) within group (order by a) from percts
where c between 1 and 2;
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.9) within group (order by a desc) from percts;
percentile_cont(0.9) within group (order by a desc) from percts;
select percentile_cont(0.1) within group (order by a),
percentile_cont(0.2) within group (order by a) from perctsz;
percentile_cont(0.2) within group (order by a) from perctsz;
select median(a - (select min(a) from percts)) from percts;
select median(a), b from perct group by b order by b desc;
select count(*) from(select median(a) from perct group by ())s;
......
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