solution.json

{
  "type": "code_options",
  "author": "csdn.net",
  "source": "solution.md",
  "exercise_id": "04eb6e04293b450d8a2149cd4b65c1a0",
  "keywords": "位运算,数学",
  "title": "两数相除",
  "desc": [
    {
      "content": "\n<p>给定两个整数，被除数&nbsp;<code>dividend</code>&nbsp;和除数&nbsp;<code>divisor</code>。将两数相除，要求不使用乘法、除法和 mod 运算符。</p><p>返回被除数&nbsp;<code>dividend</code>&nbsp;除以除数&nbsp;<code>divisor</code>&nbsp;得到的商。</p><p>整数除法的结果应当截去（<code>truncate</code>）其小数部分，例如：<code>truncate(8.345) = 8</code> 以及 <code>truncate(-2.7335) = -2</code></p><p>&nbsp;</p><p><strong>示例&nbsp;1:</strong></p><pre><strong>输入:</strong> dividend = 10, divisor = 3<strong><br />输出:</strong> 3<strong><br />解释: </strong>10/3 = truncate(3.33333..) = truncate(3) = 3</pre><p><strong>示例&nbsp;2:</strong></p><pre><strong>输入:</strong> dividend = 7, divisor = -3<strong><br />输出:</strong> -2<strong><br />解释:</strong> 7/-3 = truncate(-2.33333..) = -2</pre><p>&nbsp;</p><p><strong>提示：</strong></p><ul>\t<li>被除数和除数均为 32 位有符号整数。</li>\t<li>除数不为&nbsp;0。</li>\t<li>假设我们的环境只能存储 32 位有符号整数，其数值范围是 [&minus;2<sup>31</sup>,&nbsp; 2<sup>31&nbsp;</sup>&minus; 1]。本题中，如果除法结果溢出，则返回 2<sup>31&nbsp;</sup>&minus; 1。</li></ul>",
      "language": "markdown"
    }
  ],
  "answer": [
    {
      "content": "",
      "language": "java"
    }
  ],
  "prepared": [
    [
      {
        "content": "",
        "language": "java"
      }
    ],
    [
      {
        "content": "",
        "language": "java"
      }
    ],
    [
      {
        "content": "",
        "language": "java"
      }
    ]
  ],
  "template": {
    "content": "class Solution {\n\tpublic int divide(int dividend, int divisor) {\n\t\tif (dividend == 0) {\n\t\t\treturn 0;\n\t\t}\n\t\tif (dividend == Integer.MIN_VALUE && divisor == -1) {\n\t\t\treturn Integer.MAX_VALUE;\n\t\t}\n\t\tboolean negative;\n\t\tnegative = (dividend ^ divisor) < 0;\n\t\tlong t = Math.abs((long) dividend);\n\t\tlong d = Math.abs((long) divisor);\n\t\tint result = 0;\n\t\tfor (int i = 31; i >= 0; i--) {\n\t\t\tif ((t >> i) >= d) {\n\t\t\t\tresult += 1 << i;\n\t\t\t\tt -= d << i;\n\t\t\t}\n\t\t}\n\t\treturn negative ? -result : result;\n\t}\n}",
    "language": "java"
  },
  "node_id": "dailycode-38686faac5e447d8b52391e777bd15b5",
  "license": "csdn.net",
  "created_at": 1637894158,
  "topic_link": "https://bbs.csdn.net/topics/600470833"
}