solution.json

{
  "type": "code_options",
  "author": "csdn.net",
  "source": "solution.md",
  "exercise_id": "8517fe2b3ab94ebfaefe815949da2d20",
  "keywords": "数列,递归,数学运算",
  "title": "用递归求第n项的值",
  "desc": [
    {
      "content": "\n1，2，4，2，3，6，12，6，3，....求第n项值",
      "language": "markdown"
    }
  ],
  "answer": [
    {
      "content": "",
      "language": "cpp"
    }
  ],
  "prepared": [
    [
      {
        "content": "",
        "language": "cpp"
      }
    ],
    [
      {
        "content": "",
        "language": "cpp"
      }
    ],
    [
      {
        "content": "",
        "language": "cpp"
      }
    ]
  ],
  "template": {
    "content": "#include <stdio.h>\nint fun(int n,int *x,int *y)\n{\n\tint sum = 0,i;\n\tint size = 0;\n\tint dd = 1;\n\tfor (i = 1; i <= (*x);i++)\n\t{\n\t\tsum += (2*i-1);\n\t}\n\tif (sum == n)\n\t{\n\t\t*y = 2*(*x) -1;\n\t\treturn (*x);\n\t}else if (sum > n)\n\t{\n\t\t(*y) = n - (sum - (2 * (*x) -1));\n\t\tsize = 2* (*x) -1;\n\t\tdd = (*x);  \n\t\tfor (i = 2; i <= (*y);i++)\n\t\t{\n\t\t\tif(i <= (*x))\n\t\t\t\tdd *= 2;\n\t\t\telse\n\t\t\t\tdd /= 2;\n\t\t}\n\t\treturn dd;\n\t}else\n\t{\n\t\t(*x)++;\n\t\treturn fun(n,x,y);\n\t}\n}\nint main()\n{\n\tint n;\t\t\n\tint row = 1,col = 0;\n\tint val;\n\trow = 1;\n\tcol = 0;\n\tprintf(\"请输入n：\");\n\tscanf(\"%d\",&n);\n\tval = fun(n,&row,&col);\n\tprintf(\"第%d项是：%d\\n\",n,val);\n\treturn 0;\n}",
    "language": "cpp"
  },
  "node_id": "dailycode-42e8e695908b45c9ac0372043073d584",
  "license": "csdn.net",
  "created_at": 1637894160,
  "topic_link": "https://bbs.csdn.net/topics/600470270"
}