{
"question_id": 251110, "question_title": "筛选10到1000的回文数", "question_content": "筛选出10到1000的回文数", "difficulty": "简单", "answer_id": 249084, "answer_content": "\n\n```\n #include <stdio.h>\nint main() \n{ \n int m,n,k; \n for(m=1;m<=1000;m++) \n { \n k=m; \n n=0; \n while(k>0) \n { \n n=n*10+(k%10); \n k=k/10; \n } \n if(m==n) printf(\"%d \", m); \n }\n return 0; \n}\n```\n\n", "tag_name": "c++", "cpp": "#include <stdio.h>\nint main() \n{ \n\tint m,n,k; \n\tfor(m=1;m<=1000;m++) \n\t{ \n\t\tk=m; \n\t\tn=0; \n\t\twhile(k>0) \n\t\t{ \n\t\t\tn=n*10+(k%10); \n\t\t\tk=k/10; \n\t\t} \n\t\tif(m==n) printf(\"%d \", m); \n\t}\n\treturn 0;\t \n}", "topic_link": "https://bbs.csdn.net/topics/600470162", "status": 1, "keywords": "回文,数学运算", "license": "csdn.net", "notebook": { "cpp": "https://codechina.csdn.net/csdn/csdn-daily-code/-/jupyter/master/data/notebook/answer/ipynb/cpp/59.ipynb?type=file" }, "notebook_enable": 1, "author": "zhanjiaming"
}