add exercises

data/3.算法高阶/1.leetcode/174_组合两个表/solution.sql

+select p.FirstName,
+    p.LastName,
+    a.City,
+    a.State
+from Person p
+    left join Address a on a.PersonId = p.PersonId
\ No newline at end of file

data/3.算法高阶/1.leetcode/175_第二高的薪水/solution.sql

+select Max(Salary) SecondHighestSalary
+from Employee
+where (
+        select Max(Salary)
+        from Employee
+    ) > Salary
\ No newline at end of file

data/3.算法高阶/1.leetcode/176_第N高的薪水/solution.sql

+CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT BEGIN
+SET N := N -1;
+RETURN (
+    # Write your MySQL query statement below.
+    SELECT salary
+    FROM employee
+    GROUP BY salary
+    ORDER BY salary DESC
+    LIMIT N, 1
+);
\ No newline at end of file

data/3.算法高阶/1.leetcode/177_分数排名/solution.sql

+select Score,
+    (
+        select count(distinct Score)
+        from Scores as s2
+        where s2.Score >= s1.Score
+    ) Rank
+from Scores as s1
+order by Score DESC;
\ No newline at end of file

data/3.算法高阶/1.leetcode/179_连续出现的数字/solution.sql

+# Write your MySQL query statement below
+select distinct Num as ConsecutiveNums
+from (
+        select Num,
+            if(@pre = Num, @count := @count + 1, @count := 1) as nums,
+            @pre := Num
+        from Logs as l,
+            (
+                select @pre := null,
+                    @count := 1
+            ) as pc
+    ) as n
+where nums >= 3;
\ No newline at end of file

data/3.算法高阶/1.leetcode/180_超过经理收入的员工/solution.sql

+select name Employee
+from Employee e1
+where e1.Salary > (
+        select e2.Salary fromEmployee e2
+        where e1.ManagerId = e2.Id
+    )
\ No newline at end of file

data/3.算法高阶/1.leetcode/181_查找重复的电子邮箱/solution.sql

+select Email
+from Person
+group by Email
+having count(Email) > 1;
\ No newline at end of file

data/3.算法高阶/1.leetcode/182_从不订购的客户/solution.sql

+select c.name Customers
+from Customers c
+    left join Orders o on o.CustomerId = c.Id
+where o.CustomerId is null
\ No newline at end of file

data/3.算法高阶/1.leetcode/183_部门工资最高的员工/solution.sql

+SELECT d.NAME AS 'Department',
+    e.NAME AS 'Employee',
+    e.Salary
+FROM employee e
+    JOIN department d ON e.departmentId = d.Id
+WHERE (e.departmentId, e.Salary) IN (
+        SELECT departmentId,
+            Max(Salary)
+        FROM employee
+        GROUP BY departmentId
+    );
\ No newline at end of file

data/3.算法高阶/1.leetcode/184_部门工资前三高的所有员工/solution.sql

+SELECT Department.Name AS Department,
+    e1.Name AS Employee,
+    e1.Salary AS Salary
+FROM Employee e1
+    JOIN Department ON e1.DepartmentId = Department.Id
+WHERE 3 > (
+        SELECT COUNT(DISTINCT e2.Salary)
+        FROM Employee e2
+        WHERE e2.Salary > e1.Salary
+            AND e1.DepartmentId = e2.DepartmentId
+    )
+ORDER BY Department.Name,
+    e1.Salary DESC
\ No newline at end of file

leetcode_helper.py

@@ -27,8 +27,17 @@ def leetcode_helper():
             shutil.copy(cpp_code_src_path, cpp_code_dst_path)
         else:
             cpp_code_dst_path = os.path.join(dir, 'solution.cpp')
+            shell_code_dst_path = os.path.join(dir, 'solution.sh')
+            sql_code_dst_path = os.path.join(dir, 'solution.sql')
+
             if not os.path.exists(cpp_code_dst_path):
                 open(cpp_code_dst_path, 'w', encoding='utf-8')
+            
+            if 100 <= int(exercises_id) and int(exercises_id) < 203:
+                with open(cpp_code_dst_path, 'r', encoding='utf-8') as f:
+                        cpp_code = f.read()
+                if cpp_code == '' and not os.path.exists(shell_code_dst_path) and not os.path.exists(sql_code_dst_path):
+                    print(cpp_code_dst_path)
             desc_src_path = os.path.join(crawer_leetcode_dir, str(int(exercises_id) + 1) + '.html')
             desc_dst_path = os.path.join(dir, 'desc.html')
             # print(desc_src_path)
@@ -36,9 +45,11 @@ def leetcode_helper():
 
             if os.path.exists(desc_src_path):
                 shutil.copy(desc_src_path, desc_dst_path)
-            else:
 
-                print("该路径不存在，请检查： {}".format(desc_src_path))
+                
+            else:
+                pass
+                # print("该路径不存在，请检查： {}".format(desc_src_path))