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<div class="subTitle">cn.byk.pandora.avatarview.rule</div>
<h2 title="接口 IDrawingStrategy" class="title">接口 IDrawingStrategy</h2>
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<pre>public interface <span class="typeNameLabel">IDrawingStrategy</span></pre>
<div class="block">Author :  suzeyu
 Time   :  2016-11-29  下午6:02
 Blog   :  http://szysky.com
 GitHub :  https://github.com/suzeyu1992
 ClassDescription : 控件内部图片的显示策略</div>
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<td class="colFirst"><code>void</code></td>
<td class="colLast"><code><span class="memberNameLink"><a href="../../../../../cn/byk/pandora/avatarview/rule/IDrawingStrategy.html#algorithm-android.graphics.Canvas-int-int-cn.byk.pandora.avatarview.bean.ResInfo-cn.byk.pandora.avatarview.bean.DisplayInfo-">algorithm</a></span>(android.graphics.Canvas&nbsp;canvas,
         int&nbsp;childTotal,
         int&nbsp;curChild,
         <a href="../../../../../cn/byk/pandora/avatarview/bean/ResInfo.html" title="cn.byk.pandora.avatarview.bean中的类">ResInfo</a>&nbsp;res,
         <a href="../../../../../cn/byk/pandora/avatarview/bean/DisplayInfo.html" title="cn.byk.pandora.avatarview.bean中的类">DisplayInfo</a>&nbsp;info)</code>
<div class="block">根据提供的画布, 和可绘制的位置实现具体效果</div>
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<h4>algorithm</h4>
<pre>void&nbsp;algorithm(android.graphics.Canvas&nbsp;canvas,
               int&nbsp;childTotal,
               int&nbsp;curChild,
               <a href="../../../../../cn/byk/pandora/avatarview/bean/ResInfo.html" title="cn.byk.pandora.avatarview.bean中的类">ResInfo</a>&nbsp;res,
               <a href="../../../../../cn/byk/pandora/avatarview/bean/DisplayInfo.html" title="cn.byk.pandora.avatarview.bean中的类">DisplayInfo</a>&nbsp;info)</pre>
<div class="block">根据提供的画布, 和可绘制的位置实现具体效果</div>
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<dt><span class="paramLabel">参数:</span></dt>
<dd><code>canvas</code> - <a href="../../../../../cn/byk/pandora/avatarview/AvatarView.html#onDraw-android.graphics.Canvas-"><code>AvatarView.onDraw(Canvas)</code></a> 中的画布</dd>
<dd><code>childTotal</code> - 图片的总个数</dd>
<dd><code>curChild</code> - 当前图片是第几张图片</dd>
<dd><code>res</code> - 需要操作的资源</dd>
<dd><code>info</code> - 每个内部元素应该摆放的位置信息类</dd>
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