未验证 提交 bc2ac777 编写于 作者: K Keqi Huang 提交者: GitHub

Merge pull request #242 from xshahq/master

第59题
# 59. Spiral Matrix II
**<font color=red>难度:Medium<font>**
## 刷题内容
> 原题连接
* https://leetcode.com/problems/spiral-matrix-ii/
> 内容描述
```
Given a positive integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
Example:
Input: 3
Output:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
```
> 思路1
******- 时间复杂度: O(n^2)******- 空间复杂度: O(n^2)******
和之前的旋转遍历矩阵一样的方法,只不过这里我们要先分配一个矩阵储存,因为vector数组不好操作。
```cpp
class Solution {
public:
vector<vector<int>> generateMatrix(int n) {
int temp[n][n];
int range = n,cur = 1;
for(int i = 0;i < (n + 1) / 2 ;++i)
{
for(int j = 0;j < range;++j)
temp[i][j + i] = cur++;
for(int j = 1;j < range;++j)
temp[i + j][i + range - 1] = cur++;
for(int j = 1;j < range;++j)
temp[i + range - 1][range + i - 1 -j] = cur++;
for(int j = 1;j < range - 1;++j)
temp[range + i - 1 - j][i] = cur++;
range -= 2;
}
vector<vector<int> > ans;
for(int i = 0;i < n;++i)
{
vector<int> v;
for(int j = 0;j < n;++j)
v.push_back(temp[i][j]);
ans.push_back(v);
}
return ans;
}
};
```
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