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体验新版 GitCode,发现更多精彩内容 >>
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ad477b91
编写于
10月 11, 2017
作者:
Y
Yancey1989
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差异文件
update
上级
e880a356
变更
2
隐藏空白更改
内联
并排
Showing
2 changed file
with
17 addition
and
15 deletion
+17
-15
paddle/operators/sequence_concat_op.cc
paddle/operators/sequence_concat_op.cc
+5
-0
paddle/operators/sequence_concat_op.h
paddle/operators/sequence_concat_op.h
+12
-15
未找到文件。
paddle/operators/sequence_concat_op.cc
浏览文件 @
ad477b91
...
@@ -75,17 +75,22 @@ class SequenceConcatOpMaker : public framework::OpProtoAndCheckerMaker {
...
@@ -75,17 +75,22 @@ class SequenceConcatOpMaker : public framework::OpProtoAndCheckerMaker {
If the axis is other than 0(here, axis is 1 and level is 1),
If the axis is other than 0(here, axis is 1 and level is 1),
each input should have the same LoD information and the LoD
each input should have the same LoD information and the LoD
information of the output keeps the same as the input.
information of the output keeps the same as the input.
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,2,4}, {0,1,2,3,4}}; Dims(x1) = (4,4,4)
LoD(x1) = {{0,2,4}, {0,1,2,3,4}}; Dims(x1) = (4,4,4)
LoD(Out) = {{0,2,4}, {0,1,2,3,4}}; Dims(Out) = (4,7,4)
LoD(Out) = {{0,2,4}, {0,1,2,3,4}}; Dims(Out) = (4,7,4)
- Case2:
- Case2:
If the axis is 0(here, leve is 0), the inputs are concatenated along
If the axis is 0(here, leve is 0), the inputs are concatenated along
time steps, the LoD information of the output need to re-compute.
time steps, the LoD information of the output need to re-compute.
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,3,5}, {0,1,2,3,5}}; Dims(x1) = (5,3,4)
LoD(x1) = {{0,3,5}, {0,1,2,3,5}}; Dims(x1) = (5,3,4)
LoD(Out) = {{0,5,9}, {0,1,2,3,4,5,6,7,9}}; Dims(Out) = (9,3,4)
LoD(Out) = {{0,5,9}, {0,1,2,3,4,5,6,7,9}}; Dims(Out) = (9,3,4)
- Case3:
- Case3:
If the axis is 0(here, level is 1).
If the axis is 0(here, level is 1).
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,3,5}, {0,1,3,4,5}}; Dims(x1) = (5,3,4)
LoD(x1) = {{0,3,5}, {0,1,3,4,5}}; Dims(x1) = (5,3,4)
LoD(Out) = {{0,5,9}, {0,2,5,7,9}}; Dims(Out) = (9,3,4)
LoD(Out) = {{0,5,9}, {0,2,5,7,9}}; Dims(Out) = (9,3,4)
...
...
paddle/operators/sequence_concat_op.h
浏览文件 @
ad477b91
...
@@ -29,22 +29,19 @@ LoD concatLoD(const std::vector<const T*> ins, const size_t axis,
...
@@ -29,22 +29,19 @@ LoD concatLoD(const std::vector<const T*> ins, const size_t axis,
auto
out_lod
=
ins
[
0
]
->
lod
();
auto
out_lod
=
ins
[
0
]
->
lod
();
const
size_t
n
=
ins
.
size
();
const
size_t
n
=
ins
.
size
();
if
(
axis
==
0UL
)
{
if
(
axis
==
0UL
)
{
if
(
level
==
0UL
)
{
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
out_lod
[
0
][
j
]
+=
ins
[
i
]
->
lod
()[
0
][
j
];
out_lod
[
0
][
j
]
+=
ins
[
i
]
->
lod
()[
0
][
j
];
}
}
}
}
else
if
(
level
==
1UL
)
{
PADDLE_ENFORCE_EQ
(
ins
[
0
]
->
NumLevels
(),
2UL
,
if
(
ins
[
0
]
->
NumLevels
()
==
2
)
{
"If the level is 1, all of the inputs "
for
(
size_t
j
=
1
;
j
<
ins
[
i
]
->
lod
()[
1
].
size
();
++
j
)
{
"should be the nested sequence."
);
if
(
level
==
0UL
)
{
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
out_lod
[
1
].
push_back
(
out_lod
[
1
].
back
()
+
ins
[
i
]
->
lod
()[
1
][
j
]
-
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
ins
[
i
]
->
lod
()[
1
][
j
-
1
]);
out_lod
[
0
].
push_back
(
ins
[
i
]
->
lod
()[
0
][
j
]);
}
else
if
(
level
==
1UL
)
{
}
out_lod
[
1
][
j
]
+=
ins
[
1
]
->
lod
()[
1
][
j
];
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
1
].
size
();
++
j
)
{
}
out_lod
[
1
][
j
]
+=
ins
[
i
]
->
lod
()[
1
][
j
];
}
}
}
}
}
}
...
...
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