提交 09c6ddcd 编写于 作者: L liaogang

clang-format cuda

上级 d7ee421b
#include <stdio.h>
#include <cuda_runtime.h>
#include <stdio.h>
#include "gtest/gtest.h"
#define CHECK_ERR(x) \
if (x != cudaSuccess) { \
fprintf(stderr,"%s in %s at line %d\n", \
cudaGetErrorString(err),__FILE__,__LINE__); \
exit(-1); \
#define CHECK_ERR(x) \
if (x != cudaSuccess) { \
fprintf(stderr, \
"%s in %s at line %d\n", \
cudaGetErrorString(err), \
__FILE__, \
__LINE__); \
exit(-1); \
}
__global__ void vecAdd (float* d_A, float* d_B, float* d_C, int n) {
__global__ void vecAdd(float *d_A, float *d_B, float *d_C, int n) {
int i = blockDim.x * blockIdx.x + threadIdx.x;
if (i < n) {
d_C[i] = d_A[i] + d_B[i];
......@@ -19,35 +22,35 @@ __global__ void vecAdd (float* d_A, float* d_B, float* d_C, int n) {
TEST(Cuda, Equality) {
int n = 10;
// Memory allocation for h_A, h_B and h_C (in the host)
float h_A[10] = { 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 0.0 };
float h_B[10] = { 0.0, 9.0, 8.0, 7.0, 6.0, 5.0, 4.0, 3.0, 2.0, 1.0 };
float h_A[10] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 0.0};
float h_B[10] = {0.0, 9.0, 8.0, 7.0, 6.0, 5.0, 4.0, 3.0, 2.0, 1.0};
float h_C[10];
float *d_A, *d_B, *d_C;
cudaError_t err;
// Memory allocation for d_A, d_B and d_C (in the device)
err = cudaMalloc((void **) &d_A, sizeof(float)*n);
err = cudaMalloc((void **)&d_A, sizeof(float) * n);
CHECK_ERR(err);
err =cudaMalloc((void **) &d_B, sizeof(float)*n);
err = cudaMalloc((void **)&d_B, sizeof(float) * n);
CHECK_ERR(err);
err =cudaMalloc((void **) &d_C, sizeof(float)*n);
err = cudaMalloc((void **)&d_C, sizeof(float) * n);
CHECK_ERR(err);
// Copying memory to device
err = cudaMemcpy(d_A, h_A, sizeof(float)*n, cudaMemcpyHostToDevice);
err = cudaMemcpy(d_A, h_A, sizeof(float) * n, cudaMemcpyHostToDevice);
CHECK_ERR(err);
err = cudaMemcpy(d_B, h_B, sizeof(float)*n, cudaMemcpyHostToDevice);
err = cudaMemcpy(d_B, h_B, sizeof(float) * n, cudaMemcpyHostToDevice);
CHECK_ERR(err);
// Calling the kernel
vecAdd<<<ceil(n/256.0), 256>>>(d_A,d_B,d_C,n);
vecAdd<<<ceil(n / 256.0), 256>>>(d_A, d_B, d_C, n);
// Copying results back to host
err = cudaMemcpy(h_C, d_C, sizeof(float)*n, cudaMemcpyDeviceToHost);
err = cudaMemcpy(h_C, d_C, sizeof(float) * n, cudaMemcpyDeviceToHost);
CHECK_ERR(err);
EXPECT_EQ(h_C[0], 1.0);
for (int i = 1; i < n - 1; ++i) {
EXPECT_EQ(h_C[i], 11.0);
......
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