Skip to content
体验新版
项目
组织
正在加载...
登录
切换导航
打开侧边栏
BaiXuePrincess
Paddle
提交
09c6ddcd
P
Paddle
项目概览
BaiXuePrincess
/
Paddle
与 Fork 源项目一致
Fork自
PaddlePaddle / Paddle
通知
1
Star
1
Fork
0
代码
文件
提交
分支
Tags
贡献者
分支图
Diff
Issue
0
列表
看板
标记
里程碑
合并请求
0
Wiki
0
Wiki
分析
仓库
DevOps
项目成员
Pages
P
Paddle
项目概览
项目概览
详情
发布
仓库
仓库
文件
提交
分支
标签
贡献者
分支图
比较
Issue
0
Issue
0
列表
看板
标记
里程碑
合并请求
0
合并请求
0
Pages
分析
分析
仓库分析
DevOps
Wiki
0
Wiki
成员
成员
收起侧边栏
关闭侧边栏
动态
分支图
创建新Issue
提交
Issue看板
提交
09c6ddcd
编写于
5月 17, 2017
作者:
L
liaogang
浏览文件
操作
浏览文件
下载
电子邮件补丁
差异文件
clang-format cuda
上级
d7ee421b
变更
1
隐藏空白更改
内联
并排
Showing
1 changed file
with
21 addition
and
18 deletion
+21
-18
paddle/majel/test/cuda_test.cu
paddle/majel/test/cuda_test.cu
+21
-18
未找到文件。
paddle/majel/test/cuda_test.cu
浏览文件 @
09c6ddcd
#include <stdio.h>
#include <cuda_runtime.h>
#include <stdio.h>
#include "gtest/gtest.h"
#define CHECK_ERR(x) \
if (x != cudaSuccess) { \
fprintf(stderr,"%s in %s at line %d\n", \
cudaGetErrorString(err),__FILE__,__LINE__); \
exit(-1); \
#define CHECK_ERR(x) \
if (x != cudaSuccess) { \
fprintf(stderr, \
"%s in %s at line %d\n", \
cudaGetErrorString(err), \
__FILE__, \
__LINE__); \
exit(-1); \
}
__global__
void
vecAdd
(
float
*
d_A
,
float
*
d_B
,
float
*
d_C
,
int
n
)
{
__global__
void
vecAdd
(
float
*
d_A
,
float
*
d_B
,
float
*
d_C
,
int
n
)
{
int
i
=
blockDim
.
x
*
blockIdx
.
x
+
threadIdx
.
x
;
if
(
i
<
n
)
{
d_C
[
i
]
=
d_A
[
i
]
+
d_B
[
i
];
...
...
@@ -19,35 +22,35 @@ __global__ void vecAdd (float* d_A, float* d_B, float* d_C, int n) {
TEST
(
Cuda
,
Equality
)
{
int
n
=
10
;
// Memory allocation for h_A, h_B and h_C (in the host)
float
h_A
[
10
]
=
{
1.0
,
2.0
,
3.0
,
4.0
,
5.0
,
6.0
,
7.0
,
8.0
,
9.0
,
0.0
};
float
h_B
[
10
]
=
{
0.0
,
9.0
,
8.0
,
7.0
,
6.0
,
5.0
,
4.0
,
3.0
,
2.0
,
1.0
};
float
h_A
[
10
]
=
{
1.0
,
2.0
,
3.0
,
4.0
,
5.0
,
6.0
,
7.0
,
8.0
,
9.0
,
0.0
};
float
h_B
[
10
]
=
{
0.0
,
9.0
,
8.0
,
7.0
,
6.0
,
5.0
,
4.0
,
3.0
,
2.0
,
1.0
};
float
h_C
[
10
];
float
*
d_A
,
*
d_B
,
*
d_C
;
cudaError_t
err
;
// Memory allocation for d_A, d_B and d_C (in the device)
err
=
cudaMalloc
((
void
**
)
&
d_A
,
sizeof
(
float
)
*
n
);
err
=
cudaMalloc
((
void
**
)
&
d_A
,
sizeof
(
float
)
*
n
);
CHECK_ERR
(
err
);
err
=
cudaMalloc
((
void
**
)
&
d_B
,
sizeof
(
float
)
*
n
);
err
=
cudaMalloc
((
void
**
)
&
d_B
,
sizeof
(
float
)
*
n
);
CHECK_ERR
(
err
);
err
=
cudaMalloc
((
void
**
)
&
d_C
,
sizeof
(
float
)
*
n
);
err
=
cudaMalloc
((
void
**
)
&
d_C
,
sizeof
(
float
)
*
n
);
CHECK_ERR
(
err
);
// Copying memory to device
err
=
cudaMemcpy
(
d_A
,
h_A
,
sizeof
(
float
)
*
n
,
cudaMemcpyHostToDevice
);
err
=
cudaMemcpy
(
d_A
,
h_A
,
sizeof
(
float
)
*
n
,
cudaMemcpyHostToDevice
);
CHECK_ERR
(
err
);
err
=
cudaMemcpy
(
d_B
,
h_B
,
sizeof
(
float
)
*
n
,
cudaMemcpyHostToDevice
);
err
=
cudaMemcpy
(
d_B
,
h_B
,
sizeof
(
float
)
*
n
,
cudaMemcpyHostToDevice
);
CHECK_ERR
(
err
);
// Calling the kernel
vecAdd
<<<
ceil
(
n
/
256.0
),
256
>>>
(
d_A
,
d_B
,
d_C
,
n
);
vecAdd
<<<
ceil
(
n
/
256.0
),
256
>>>
(
d_A
,
d_B
,
d_C
,
n
);
// Copying results back to host
err
=
cudaMemcpy
(
h_C
,
d_C
,
sizeof
(
float
)
*
n
,
cudaMemcpyDeviceToHost
);
err
=
cudaMemcpy
(
h_C
,
d_C
,
sizeof
(
float
)
*
n
,
cudaMemcpyDeviceToHost
);
CHECK_ERR
(
err
);
EXPECT_EQ
(
h_C
[
0
],
1.0
);
for
(
int
i
=
1
;
i
<
n
-
1
;
++
i
)
{
EXPECT_EQ
(
h_C
[
i
],
11.0
);
...
...
编辑
预览
Markdown
is supported
0%
请重试
或
添加新附件
.
添加附件
取消
You are about to add
0
people
to the discussion. Proceed with caution.
先完成此消息的编辑!
取消
想要评论请
注册
或
登录