Update Leetcode 题解.md

docs/notes/Leetcode 题解.md

@@ -3050,7 +3050,6 @@ public boolean canPartition(int[] nums) {
     int W = sum / 2;
     boolean[] dp = new boolean[W + 1];
     dp[0] = true;
-    Arrays.sort(nums);
     for (int num : nums) {                 // 0-1 背包一个物品只能用一次
         for (int i = W; i >= num; i--) {   // 从后往前，先计算 dp[i] 再计算 dp[i-num]
             dp[i] = dp[i] || dp[i - num];