# Copyright (c) 2018 PaddlePaddle Authors. All Rights Reserve. # #Licensed under the Apache License, Version 2.0 (the "License"); #you may not use this file except in compliance with the License. #You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # #Unless required by applicable law or agreed to in writing, software #distributed under the License is distributed on an "AS IS" BASIS, #WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. #See the License for the specific language governing permissions and #limitations under the License. # Logic copied from PEP 513 def is_manylinux1_compatible(): # Only Linux, and only x86-64 / i686 from distutils.util import get_platform if get_platform() not in ["linux-x86_64", "linux-i686"]: return False # Check for presence of _manylinux module try: import _manylinux return bool(_manylinux.manylinux1_compatible) except (ImportError, AttributeError): # Fall through to heuristic check below pass # Check glibc version. CentOS 5 uses glibc 2.5. return have_compatible_glibc(2, 5) def have_compatible_glibc(major, minimum_minor): import ctypes process_namespace = ctypes.CDLL(None) try: gnu_get_libc_version = process_namespace.gnu_get_libc_version except AttributeError: # Symbol doesn't exist -> therefore, we are not linked to # glibc. return False # Call gnu_get_libc_version, which returns a string like "2.5". gnu_get_libc_version.restype = ctypes.c_char_p version_str = gnu_get_libc_version() # py2 / py3 compatibility: if not isinstance(version_str, str): version_str = version_str.decode("ascii") # Parse string and check against requested version. version = [int(piece) for piece in version_str.split(".")] assert len(version) == 2 if major != version[0]: return False if minimum_minor > version[1]: return False return True import sys if is_manylinux1_compatible(): print("%s is manylinux1 compatible" % (sys.executable, )) sys.exit(0) else: print("%s is NOT manylinux1 compatible" % (sys.executable, )) sys.exit(1)