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b3afe30d
编写于
9月 06, 2017
作者:
C
Cao Ying
提交者:
GitHub
9月 06, 2017
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差异文件
Merge pull request #3887 from lcy-seso/update_softmax_doc
update the doc of softmax_op.
上级
ba43904a
dc520da7
变更
1
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Showing
1 changed file
with
22 addition
and
4 deletion
+22
-4
paddle/operators/softmax_op.cc
paddle/operators/softmax_op.cc
+22
-4
未找到文件。
paddle/operators/softmax_op.cc
浏览文件 @
b3afe30d
...
...
@@ -24,7 +24,7 @@ class SoftmaxOp : public framework::OperatorWithKernel {
protected:
void
InferShape
(
const
framework
::
InferShapeContext
&
ctx
)
const
override
{
PADDLE_ENFORCE
(
ctx
.
Input
<
Tensor
>
(
"X"
)
->
dims
().
size
()
==
2UL
,
"The input of softmax op must be
matrix
"
);
"The input of softmax op must be
a matrix.
"
);
ctx
.
Output
<
Tensor
>
(
"Y"
)
->
Resize
(
ctx
.
Input
<
Tensor
>
(
"X"
)
->
dims
());
}
};
...
...
@@ -34,9 +34,27 @@ class SoftmaxOpMaker : public framework::OpProtoAndCheckerMaker {
SoftmaxOpMaker
(
framework
::
OpProto
*
proto
,
framework
::
OpAttrChecker
*
op_checker
)
:
OpProtoAndCheckerMaker
(
proto
,
op_checker
)
{
AddInput
(
"X"
,
"input of softmax"
);
AddOutput
(
"Y"
,
"output of softmax"
);
AddComment
(
"Softmax Op"
);
AddInput
(
"X"
,
"The input tensor of softmax. "
"2-D with shape [batch_size, input_feature_dimensions]."
);
AddOutput
(
"Y"
,
"The normalized values with the same shape as X."
);
AddComment
(
R"DOC(
The input of softmax operator is a 2-D tensor with shape N x K (N is the
batch_size, K is the dimension of input feature). The output tensor has the
same shape as the input tensor.
For each row of the input tensor, the softmax operator squashes the
K-dimensional vector of arbitrary real values to a K-dimensional vector of real
values in the range [0, 1] that add up to 1. Specifically, it computes the
exponential of the given dimension and the sum of exponential values of all
the other dimensions in the K-dimensional vector input. Then the ratio of the
exponential of the given dimension and the sum of exponential values of all
the other dimensions is the output of the softmax operator.
For each row `i` and each column `j` in X, we have:
Y[i, j] = exp(X[i, j]) / sum_j(exp(X[i, j]))
)DOC"
);
}
};
...
...
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