[PATCH] sched: don't print migration cost when only 1 CPU

If only a single CPU is present, printing this doesn't make much sense.
Signed-off-by: NDave Jones <davej@redhat.com>
Acked-by: NIngo Molnar <mingo@elte.hu>
Acked-by: NNick Piggin <nickpiggin@yahoo.com.au>
Signed-off-by: NAndrew Morton <akpm@osdl.org>
Signed-off-by: NLinus Torvalds <torvalds@osdl.org>

kernel/sched.c

@@ -5977,6 +5977,7 @@ static void calibrate_migration_costs(const cpumask_t *cpu_map)
 #endif
 		);
 	if (system_state == SYSTEM_BOOTING) {
+		if (num_online_cpus() > 1) {
 			printk("migration_cost=");
 			for (distance = 0; distance <= max_distance; distance++) {
 				if (distance)
@@ -5985,6 +5986,7 @@ static void calibrate_migration_costs(const cpumask_t *cpu_map)
 			}
 			printk("\n");
 		}
+	}
 	j1 = jiffies;
 	if (migration_debug)
 		printk("migration: %ld seconds\n", (j1-j0)/HZ);