ipmi_si: fix potential integer overflow on large shift

mainline inclusion
from mainline-4.20-rc1
commit 97a103e6
category: bugfix
bugzilla: 6325
CVE: NA

---------------------------

Shifting unsigned char b by an int type can lead to sign-extension
overflow. For example, if b is 0xff and the shift is 24, then top
bit is sign-extended so the final value passed to writeq has all
the upper 32 bits set.  Fix this by casting b to a 64 bit unsigned
before the shift.

Detected by CoverityScan, CID#1465246 ("Unintended sign extension")
Signed-off-by: NColin Ian King <colin.king@canonical.com>
Signed-off-by: NCorey Minyard <cminyard@mvista.com>
Signed-off-by: NJason Yan <yanaijie@huawei.com>
Reviewed-by: Nzhengbin <zhengbin13@huawei.com>
Signed-off-by: NYang Yingliang <yangyingliang@huawei.com>

drivers/char/ipmi/ipmi_si_mem_io.c

@@ -51,7 +51,7 @@ static unsigned char mem_inq(const struct si_sm_io *io, unsigned int offset)
 static void mem_outq(const struct si_sm_io *io, unsigned int offset,
 		     unsigned char b)
 {
-	writeq(b << io->regshift, (io->addr)+(offset * io->regspacing));
+	writeq((u64)b << io->regshift, (io->addr)+(offset * io->regspacing));
 }
 #endif