提交 356557be 编写于 作者: J Jan Kara

udf: Clarify meaning of f_files in udf_statfs

UDF does not have separate preallocated table of inodes. So similarly to
XFS we pretend that every free block is also a free inode in statfs(2)
output. Clarify this in a comment.
Signed-off-by: NJan Kara <jack@suse.cz>
上级 15fb05fd
...@@ -2402,6 +2402,10 @@ static int udf_statfs(struct dentry *dentry, struct kstatfs *buf) ...@@ -2402,6 +2402,10 @@ static int udf_statfs(struct dentry *dentry, struct kstatfs *buf)
buf->f_blocks = sbi->s_partmaps[sbi->s_partition].s_partition_len; buf->f_blocks = sbi->s_partmaps[sbi->s_partition].s_partition_len;
buf->f_bfree = udf_count_free(sb); buf->f_bfree = udf_count_free(sb);
buf->f_bavail = buf->f_bfree; buf->f_bavail = buf->f_bfree;
/*
* Let's pretend each free block is also a free 'inode' since UDF does
* not have separate preallocated table of inodes.
*/
buf->f_files = (lvidiu != NULL ? (le32_to_cpu(lvidiu->numFiles) + buf->f_files = (lvidiu != NULL ? (le32_to_cpu(lvidiu->numFiles) +
le32_to_cpu(lvidiu->numDirs)) : 0) le32_to_cpu(lvidiu->numDirs)) : 0)
+ buf->f_bfree; + buf->f_bfree;
......
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