提交 2c54c86a 编写于 作者: J James C Boyd 提交者: Jiri Kosina

HID: hid-input: Simplify conditional expression

There are too many bangs in this conditional; therefore
remove them while still maintaining the same logic.
Signed-off-by: NJames C Boyd <jcboyd.dev@gmail.com>
Signed-off-by: NJiri Kosina <jkosina@suse.cz>
上级 09a5c34e
......@@ -1157,7 +1157,7 @@ void hidinput_hid_event(struct hid_device *hid, struct hid_field *field, struct
return;
/* report the usage code as scancode if the key status has changed */
if (usage->type == EV_KEY && (!!test_bit(usage->code, input->key)) != value)
if (usage->type == EV_KEY && (!test_bit(usage->code, input->key)) == value)
input_event(input, EV_MSC, MSC_SCAN, usage->hid);
input_event(input, usage->type, usage->code, value);
......
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