提交 21f28e6f 编写于 作者: F Felix Fietkau 提交者: John W. Linville

ath9k: try more than one tid when scheduling a new aggregate

Sometimes the first TID in the first AC's list is not available for forming
a new aggregate (the BAW might not allow it), however other TIDs may have
data available for sending.
Prevent a slowdown of other TIDs by going through multiple entries until
we've either hit the last one or enough AMPDUs are pending in the hardware
queue.
Signed-off-by: NFelix Fietkau <nbd@openwrt.org>
Signed-off-by: NJohn W. Linville <linville@tuxdriver.com>
上级 a4d6e17d
......@@ -1224,12 +1224,14 @@ void ath_tx_cleanupq(struct ath_softc *sc, struct ath_txq *txq)
void ath_txq_schedule(struct ath_softc *sc, struct ath_txq *txq)
{
struct ath_atx_ac *ac;
struct ath_atx_tid *tid;
struct ath_atx_tid *tid, *last;
if (list_empty(&txq->axq_acq))
if (list_empty(&txq->axq_acq) ||
txq->axq_ampdu_depth >= ATH_AGGR_MIN_QDEPTH)
return;
ac = list_first_entry(&txq->axq_acq, struct ath_atx_ac, list);
last = list_entry(ac->tid_q.prev, struct ath_atx_tid, list);
list_del(&ac->list);
ac->sched = false;
......@@ -1253,6 +1255,7 @@ void ath_txq_schedule(struct ath_softc *sc, struct ath_txq *txq)
if (!list_empty(&tid->buf_q))
ath_tx_queue_tid(txq, tid);
if (tid == last || txq->axq_ampdu_depth >= ATH_AGGR_MIN_QDEPTH)
break;
} while (!list_empty(&ac->tid_q));
......
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