提交 5483f799 编写于 作者: J Jeff King 提交者: Junio C Hamano

refactor find_ref_by_name() to accept const list

Since it doesn't actually touch its argument, this makes
sense.

However, we still want to return a non-const version (which
requires a cast) so that this:

  struct ref *a, *b;
  a = find_ref_by_name(b);

works. Unfortunately, you can also silently strip the const
from a variable:

  struct ref *a;
  const struct ref *b;
  a = find_ref_by_name(b);

This is a classic C const problem because there is no way to
say "return the type with the same constness that was passed
to us"; we provide the same semantics as standard library
functions like strchr.
Signed-off-by: NJeff King <peff@peff.net>
Signed-off-by: NJay Soffian <jaysoffian@gmail.com>
Signed-off-by: NJunio C Hamano <gitster@pobox.com>
上级 119c8eee
......@@ -801,7 +801,7 @@ struct ref {
#define REF_HEADS (1u << 1)
#define REF_TAGS (1u << 2)
extern struct ref *find_ref_by_name(struct ref *list, const char *name);
extern struct ref *find_ref_by_name(const struct ref *list, const char *name);
#define CONNECT_VERBOSE (1u << 0)
extern struct child_process *git_connect(int fd[2], const char *url, const char *prog, int flags);
......
......@@ -1628,10 +1628,10 @@ int update_ref(const char *action, const char *refname,
return 0;
}
struct ref *find_ref_by_name(struct ref *list, const char *name)
struct ref *find_ref_by_name(const struct ref *list, const char *name)
{
for ( ; list; list = list->next)
if (!strcmp(list->name, name))
return list;
return (struct ref *)list;
return NULL;
}
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