{ "type": "code_options", "author": "https://github.com/begeekmyfriend/leetcode", "source": "solution.md", "exercise_id": "2ccf0ab29b484a67a42e6aa7b5387498", "keywords": "数组,数学,矩阵", "title": "旋转图像", "desc": [ { "content": "\n

给定一个 × n 的二维矩阵 matrix 表示一个图像。请你将图像顺时针旋转 90 度。

你必须在 原地 旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要 使用另一个矩阵来旋转图像。

 

示例 1:

\"\"
输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:
[[7,4,1],[8,5,2],[9,6,3]]

示例 2:

\"\"
输入:matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
输出:
[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

示例 3:

输入:matrix = [[1]]
输出:
[[1]]

示例 4:

输入:matrix = [[1,2],[3,4]]
输出:
[[3,1],[4,2]]

 

提示:

", "language": "markdown" } ], "answer": [ { "content": "", "language": "cpp" } ], "prepared": [ [ { "content": "", "language": "cpp" } ], [ { "content": "", "language": "cpp" } ], [ { "content": "", "language": "cpp" } ] ], "template": { "content": "#include \nusing namespace std;\nclass Solution\n{\npublic:\n\tvoid rotate(vector> &matrix)\n\t{\n\t\tint size = matrix.size();\n\t\tfor (int i = 0; i < size / 2; i++)\n\t\t{\n\t\t\tint low = i, high = size - i - 1;\n\t\t\tfor (int j = low; j < high; j++)\n\t\t\t{\n\t\t\t\tint tmp = matrix[i][j];\n\t\t\t\tmatrix[i][j] = matrix[size - 1 - j][i];\n\t\t\t\tmatrix[size - 1 - j][i] = matrix[size - 1 - i][size - 1 - j];\n\t\t\t\tmatrix[size - 1 - i][size - 1 - j] = matrix[j][size - 1 - i];\n\t\t\t\tmatrix[j][size - 1 - i] = tmp;\n\t\t\t}\n\t\t}\n\t}\n};", "language": "cpp" }, "node_id": "dailycode-cb4872e5db3e4e259d3f87e69917426c", "license": "csdn.net", "created_at": 1637894158, "topic_link": "https://bbs.csdn.net/topics/600470225" }