{
  "question_id": 7457297,
  "question_title": "找出小于平均值的数。",
  "question_content": "<p>从键盘输入一个正整数存入变量n中&#xff0c;再输入n个整数&#xff0c;然后找出所有小于平均值的数&#xff0c;并按输入顺序输出。\n \n </p>",
  "difficulty": "简单",
  "answer_id": 53441440,
  "answer_content": "<pre>\n<code>#include&lt;stdio.h&gt;\n\nint main()\n{\n\tint i,n,x,sum&#61;0,a[100];\n\tfloat ave;\n\tscanf(&#34;%d&#34;,&amp;n);\n\tfor(i&#61;0;i&lt;n;i&#43;&#43;){\n        scanf(&#34;%d&#34;,&amp;a[i]);\n        sum&#43;&#61;a[i];\n\t}\n\tave&#61;sum*1.0/n;\n\tfor(i&#61;0;i&lt;n;i&#43;&#43;){\n        if(a[i]&lt;ave)\n            printf(&#34;%d&#34;,a[i]);\n\t}\n\n\treturn 0;\n\n}\n</code></pre>\n\n<p> </p>\n",
  "tag_name": "c语言",
  "cpp": "#include<stdio.h>\nint main()\n{\n\tint i,n,sum=0,a[100];\n\tfloat ave;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t\tsum+=a[i];\n\t}\n\tave=sum*1.0/n;\n\tfor(i=0;i<n;i++){\n\t\tif(a[i]<ave)\n\t\t\tprintf(\"%d\",a[i]);\n\t}\n\treturn 0;\n}",
  "topic_link": "https://bbs.csdn.net/topics/600470164",
  "status": 1,
  "keywords": "算法初阶,排序和顺序统计量,中位数和顺序统计量",
  "license": "csdn.net",
  "notebook": {
    "cpp": "https://codechina.csdn.net/csdn/csdn-daily-code/-/jupyter/master/data/notebook/answer/ipynb/cpp/71.ipynb?type=file"
  },
  "notebook_enable": 1,
  "author": "bonze1023"
}