# 文本左右对齐

给定一个单词数组和一个长度 maxWidth,重新排版单词,使其成为每行恰好有 maxWidth 个字符,且左右两端对齐的文本。

你应该使用“贪心算法”来放置给定的单词;也就是说,尽可能多地往每行中放置单词。必要时可用空格 ' ' 填充,使得每行恰好有 maxWidth 个字符。

要求尽可能均匀分配单词间的空格数量。如果某一行单词间的空格不能均匀分配,则左侧放置的空格数要多于右侧的空格数。

文本的最后一行应为左对齐,且单词之间不插入额外的空格。

说明:

示例:

输入:
    words = ["This", "is", "an", "example", "of", "text", "justification."]
    maxWidth = 16
输出:
    [
       "This    is    an",
       "example  of text",
       "justification.  "
    ]
    

示例 2:

输入:
    words = ["What","must","be","acknowledgment","shall","be"]
    maxWidth = 16
输出:
    [
      "What   must   be",
      "acknowledgment  ",
      "shall be        "
    ]
解释: 注意最后一行的格式应为 "shall be    " 而不是 "shall     be"
    因为最后一行应为左对齐,而不是左右两端对齐,第二行同样为左对齐,这是因为这行只包含一个单词。
    

示例 3:

输入:
    words = ["Science","is","what","we","understand","well","enough","to","explain",
             "to","a","computer.","Art","is","everything","else","we","do"]
    maxWidth = 20
输出:
    [
      "Science  is  what we",
      "understand      well",
      "enough to explain to",
      "a  computer.  Art is",
      "everything  else  we",
      "do                  "
    ]
    
以下程序实现了这一功能,请你填补空白处内容: ```java class Solution { public List fullJustify(String[] words, int maxWidth) { List ret = new ArrayList<>(); int index = 0; while (index < words.length) { int cur = index, len = 0; while (cur < words.length && len + words[cur].length() + cur - index <= maxWidth) { len = len + words[cur++].length(); } cur--; StringBuilder sb = new StringBuilder(); if (cur == words.length - 1) { for (int i = index; i <= cur; i++) { sb.append(words[i]); if (i < cur) { sb.append(' '); } } } else { int base = cur > index ? (maxWidth - len) / (cur - index) : (maxWidth - len); String baseStr = genSpace(base); int left = cur > index ? (maxWidth - len) % (cur - index) : 0; String leftStr = genSpace(base + 1); for (int i = index; i <= cur; i++) { sb.append(words[i]); ___________________; } } if (sb.length() < maxWidth) { sb.append(genSpace(maxWidth - sb.length())); } ret.add(sb.toString()); index = cur + 1; } return ret; } private String genSpace(int n) { char[] cs = new char[n]; Arrays.fill(cs, ' '); return new String(cs); } } ``` ## template ```java class Solution { public List fullJustify(String[] words, int maxWidth) { List ret = new ArrayList<>(); int index = 0; while (index < words.length) { int cur = index, len = 0; while (cur < words.length && len + words[cur].length() + cur - index <= maxWidth) { len = len + words[cur++].length(); } cur--; StringBuilder sb = new StringBuilder(); if (cur == words.length - 1) { for (int i = index; i <= cur; i++) { sb.append(words[i]); if (i < cur) { sb.append(' '); } } } else { int base = cur > index ? (maxWidth - len) / (cur - index) : (maxWidth - len); String baseStr = genSpace(base); int left = cur > index ? (maxWidth - len) % (cur - index) : 0; String leftStr = genSpace(base + 1); for (int i = index; i <= cur; i++) { sb.append(words[i]); if (i < cur) { sb.append(left > 0 ? leftStr : baseStr); left--; } } } if (sb.length() < maxWidth) { sb.append(genSpace(maxWidth - sb.length())); } ret.add(sb.toString()); index = cur + 1; } return ret; } private String genSpace(int n) { char[] cs = new char[n]; Arrays.fill(cs, ' '); return new String(cs); } } ``` ## 答案 ```java if (i < cur) { sb.append(left > 0 ? leftStr : baseStr); left--; } ``` ## 选项 ### A ```java if (i < cur) { sb.append(left > 0 ? baseStr : leftStr); left--; } ``` ### B ```java if (i < cur) { sb.append(left > 0 ? baseStr : leftStr); left++; } ``` ### C ```java if (i < cur) { sb.append(left >= 0 ? leftStr : baseStr); left--; } ```