将一个给定字符串 s
根据给定的行数 numRows
,以从上往下、从左到右进行 Z 字形排列。
比如输入字符串为 "PAYPALISHIRING"
行数为 3
时,排列如下:
P A H N
A P L S I I G
Y I R
之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:"PAHNAPLSIIGYIR"
。
请你实现这个将字符串进行指定行数变换的函数:
string convert(string s, int numRows);
示例 1:
输入:s = "PAYPALISHIRING", numRows = 3
输出:"PAHNAPLSIIGYIR"
示例 2:
输入:s = "PAYPALISHIRING", numRows = 4
输出:"PINALSIGYAHRPI"
解释:
P I N
A L S I G
Y A H R
P I
示例 3:
输入:s = "A", numRows = 1
输出:"A"
提示:
1 <= s.length <= 1000
s
由英文字母(小写和大写)、','
和 '.'
组成
1 <= numRows <= 1000
## template
```python
import math
class Solution:
def convert(self, s: str, numRows: int) -> str:
n = len(s)
N = numRows
if n == 1 or N == 1:
return s
S = N-2
C = 2*N-2
R = int(math.floor(n/C))
RS = n % (C)
CE = n-R*C
RR = 1 if (RS <= N) else 1+(RS-N)
RX = R*(N-1) + RR
output = []
i = 0
while i < N:
j = 0
k = (N-1-i)
while j < RX:
r = int(math.floor(j/(N-1)))
rs = j % (N-1)
offset = i if rs == 0 else N+rs-1
index = r*C+offset
if index < len(s):
output.append(s[index])
if i > 0 and i < N-1:
r = int(math.floor(k/(N-1)))
rs = k % (N-1)
offset = i if rs == 0 else N+rs-1
index = r*C+offset
if index < len(s):
output.append(s[index])
j += (N-1)
k += (N-1)
i += 1
return ''.join(output)
# %%
s = Solution()
print(s.convert('PAYPALISHIRING', 3))
```
## 答案
```python
```
## 选项
### A
```python
```
### B
```python
```
### C
```python
```