# Z 字形变换

将一个给定字符串 s 根据给定的行数 numRows ,以从上往下、从左到右进行 Z 字形排列。

比如输入字符串为 "PAYPALISHIRING" 行数为 3 时,排列如下:

    P   A   H   N
    A P L S I I G
    Y   I   R

之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:"PAHNAPLSIIGYIR"

请你实现这个将字符串进行指定行数变换的函数:

string convert(string s, int numRows);

 

示例 1:

输入:s = "PAYPALISHIRING", numRows = 3
输出:"PAHNAPLSIIGYIR"
示例 2:
输入:s = "PAYPALISHIRING", numRows = 4
输出:"PINALSIGYAHRPI"
解释:
P     I    N
A   L S  I G
Y A   H R
P     I

示例 3:

输入:s = "A", numRows = 1
输出:"A"

 

提示:

## template ```python import math class Solution: def convert(self, s: str, numRows: int) -> str: n = len(s) N = numRows if n == 1 or N == 1: return s S = N-2 C = 2*N-2 R = int(math.floor(n/C)) RS = n % (C) CE = n-R*C RR = 1 if (RS <= N) else 1+(RS-N) RX = R*(N-1) + RR output = [] i = 0 while i < N: j = 0 k = (N-1-i) while j < RX: r = int(math.floor(j/(N-1))) rs = j % (N-1) offset = i if rs == 0 else N+rs-1 index = r*C+offset if index < len(s): output.append(s[index]) if i > 0 and i < N-1: r = int(math.floor(k/(N-1))) rs = k % (N-1) offset = i if rs == 0 else N+rs-1 index = r*C+offset if index < len(s): output.append(s[index]) j += (N-1) k += (N-1) i += 1 return ''.join(output) # %% s = Solution() print(s.convert('PAYPALISHIRING', 3)) ``` ## 答案 ```python ``` ## 选项 ### A ```python ``` ### B ```python ``` ### C ```python ```