# 合并两个有序链表
将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例 1:
![](https://cdn.jsdelivr.net/gh/doocs/leetcode@main/solution/0000-0099/0021.Merge%20Two%20Sorted%20Lists/images/merge_ex1.jpg)
输入:l1 = [1,2,4], l2 = [1,3,4]
输出:[1,1,2,3,4,4]
示例 2:
输入:l1 = [], l2 = []
输出:[]
示例 3:
输入:l1 = [], l2 = [0]
输出:[0]
提示:
- 两个链表的节点数目范围是
[0, 50]
-100 <= Node.val <= 100
l1
和 l2
均按 非递减顺序 排列
## template
```java
public class ListNode {
int val;
ListNode next;
ListNode() {
}
ListNode(int val) {
this.val = val;
}
ListNode(int val, ListNode next) {
this.val = val;
this.next = next;
}
}
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode h = new ListNode(0, null);
ListNode p = h;
while (l1 != null && l2 != null) {
if (l1.val < l2.val) {
p.next = l1;
p = l1;
l1 = l1.next;
} else {
p.next = l2;
p = l2;
l2 = l2.next;
}
}
if (l1 != null) {
p.next = l1;
} else {
p.next = l2;
}
return h.next;
}
}
```
## 答案
```java
```
## 选项
### A
```java
```
### B
```java
```
### C
```java
```