# 汇总区间

给定一个无重复元素的有序整数数组 nums

返回 恰好覆盖数组中所有数字最小有序 区间范围列表。也就是说,nums 的每个元素都恰好被某个区间范围所覆盖,并且不存在属于某个范围但不属于 nums 的数字 x

列表中的每个区间范围 [a,b] 应该按如下格式输出:

 

示例 1:

输入:nums = [0,1,2,4,5,7]
输出:["0->2","4->5","7"]
解释:区间范围是:
[0,2] --> "0->2"
[4,5] --> "4->5"
[7,7] --> "7"

示例 2:

输入:nums = [0,2,3,4,6,8,9]
输出:["0","2->4","6","8->9"]
解释:区间范围是:
[0,0] --> "0"
[2,4] --> "2->4"
[6,6] --> "6"
[8,9] --> "8->9"

示例 3:

输入:nums = []
输出:[]

示例 4:

输入:nums = [-1]
输出:["-1"]

示例 5:

输入:nums = [0]
输出:["0"]

 

提示:

## template ```java class Solution { public List summaryRanges(int[] nums) { List list = new ArrayList<>(); int pre = 0; int next = 0; for (int i = 0; i < nums.length; i++) { if (i + 1 < nums.length && nums[i + 1] - nums[i] == 1) { next = i + 1; } else { if (next < i) next = i; if (pre != next) { list.add(nums[pre] + "->" + nums[next]); pre = i + 1; } if (pre == next) { list.add(nums[pre] + ""); pre = i + 1; } } } return list; } } ``` ## 答案 ```java ``` ## 选项 ### A ```java ``` ### B ```java ``` ### C ```java ```