# 接雨水
给定 n 个非负整数表示每个宽度为 1 的柱子的高度图,计算按此排列的柱子,下雨之后能接多少雨水。
示例 1:

输入:height = [0,1,0,2,1,0,1,3,2,1,2,1]
输出:6
解释:上面是由数组 [0,1,0,2,1,0,1,3,2,1,2,1] 表示的高度图,在这种情况下,可以接 6 个单位的雨水(蓝色部分表示雨水)。
示例 2:
输入:height = [4,2,0,3,2,5]
输出:9
提示:
n == height.length 0 <= n <= 3 * 104 0 <= height[i] <= 105
以下程序实现了这一功能,请你填补空白处的内容:
```cpp
#include
using namespace std;
class Solution
{
public:
int trap(vector &height)
{
int res = 0;
int left = 0, left_max = 0;
int right = height.size() - 1, right_max = 0;
while (left < right)
{
_____________________;
}
return res;
}
};
```
## template
```cpp
#include
using namespace std;
class Solution
{
public:
int trap(vector &height)
{
int res = 0;
int left = 0, left_max = 0;
int right = height.size() - 1, right_max = 0;
while (left < right)
{
if (height[left] < height[right])
{
if (height[left] > left_max)
{
left_max = height[left];
}
else
{
res += left_max - height[left];
}
left++;
}
else
{
if (height[right] > right_max)
{
right_max = height[right];
}
else
{
res += right_max - height[right];
}
right--;
}
}
return res;
}
};
```
## 答案
```cpp
if (height[left] < height[right])
{
if (height[left] > left_max)
{
left_max = height[left];
}
else
{
res += left_max - height[left];
}
left++;
}
else
{
if (height[right] > right_max)
{
right_max = height[right];
}
else
{
res += right_max - height[right];
}
right--;
}
```
## 选项
### A
```cpp
if (height[left] < height[right])
{
if (height[left] > left_max)
{
left_max = height[left];
}
else
{
res += left_max - height[left];
}
left--;
}
else
{
if (height[right] > right_max)
{
right_max = height[right];
}
else
{
res += right_max - height[right];
}
right++;
}
```
### B
```cpp
if (height[left] < height[right])
{
if (height[left] > left_max)
{
left_max = height[left];
}
else
{
res += left_max + height[left];
}
left++;
}
else
{
if (height[right] > right_max)
{
right_max = height[right];
}
else
{
res += right_max + height[right];
}
right--;
}
```
### C
```cpp
if (height[left] < height[right])
{
if (height[left] > left_max)
{
left_max = height[left];
}
else
{
res += left_max + height[left];
}
left--;
}
else
{
if (height[right] > right_max)
{
right_max = height[right];
}
else
{
res += right_max + height[right];
}
right++;
}
```