# 旋转图像

给定一个 × n 的二维矩阵 matrix 表示一个图像。请你将图像顺时针旋转 90 度。

你必须在 原地 旋转图像,这意味着你需要直接修改输入的二维矩阵。请不要 使用另一个矩阵来旋转图像。

 

示例 1:

输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:
[[7,4,1],[8,5,2],[9,6,3]]

示例 2:

输入:matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
输出:
[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]

示例 3:

输入:matrix = [[1]]
输出:
[[1]]

示例 4:

输入:matrix = [[1,2],[3,4]]
输出:
[[3,1],[4,2]]

 

提示:

以下程序实现了这一功能,请你填补空白处内容: ```cpp #include using namespace std; class Solution { public: void rotate(vector> &matrix) { int size = matrix.size(); for (int i = 0; i < size / 2; i++) { int low = i, high = size - i - 1; for (int j = low; j < high; j++) { int tmp = matrix[i][j]; _________________________; } } } }; ``` ## template ```cpp #include using namespace std; class Solution { public: void rotate(vector> &matrix) { int size = matrix.size(); for (int i = 0; i < size / 2; i++) { int low = i, high = size - i - 1; for (int j = low; j < high; j++) { int tmp = matrix[i][j]; matrix[i][j] = matrix[size - 1 - j][i]; matrix[size - 1 - j][i] = matrix[size - 1 - i][size - 1 - j]; matrix[size - 1 - i][size - 1 - j] = matrix[j][size - 1 - i]; matrix[j][size - 1 - i] = tmp; } } } }; ``` ## 答案 ```cpp matrix[i][j] = matrix[size - 1 - j][i]; matrix[size - 1 - j][i] = matrix[size - 1 - i][size - 1 - j]; matrix[size - 1 - i][size - 1 - j] = matrix[j][size - 1 - i]; matrix[j][size - 1 - i] = tmp; ``` ## 选项 ### A ```cpp matrix[i][j] = matrix[size - 1 - j][i]; matrix[size - 1 - j][i] = matrix[size - i][size - j]; matrix[size - 1 - i][size - j] = matrix[j][size - i]; matrix[j][size - 1 - i] = tmp; ``` ### B ```cpp matrix[i][j] = matrix[size - 1 - j][i]; matrix[size + 1 - j][i] = matrix[size + 1 - i][size + 1 - j]; matrix[size + 1 - i][size + 1 - j] = matrix[j][size + 1 - i]; matrix[j][size + 1 - i] = tmp; ``` ### C ```cpp matrix[i][j] = matrix[size - 1 - j][i]; matrix[size - 1 - j][i] = matrix[size - 1 - i][size + 1 - j]; matrix[size - 1 - i][size - 1 - j] = matrix[j][size + 1 - i]; matrix[j][size - 1 - i] = tmp; ```