# 两数相除

<p>给定两个整数，被除数&nbsp;<code>dividend</code>&nbsp;和除数&nbsp;<code>divisor</code>。将两数相除，要求不使用乘法、除法和 mod 运算符。</p><p>返回被除数&nbsp;<code>dividend</code>&nbsp;除以除数&nbsp;<code>divisor</code>&nbsp;得到的商。</p><p>整数除法的结果应当截去（<code>truncate</code>）其小数部分，例如：<code>truncate(8.345) = 8</code> 以及 <code>truncate(-2.7335) = -2</code></p><p>&nbsp;</p><p><strong>示例&nbsp;1:</strong></p><pre><strong>输入:</strong> dividend = 10, divisor = 3<strong><br />输出:</strong> 3<strong><br />解释: </strong>10/3 = truncate(3.33333..) = truncate(3) = 3</pre><p><strong>示例&nbsp;2:</strong></p><pre><strong>输入:</strong> dividend = 7, divisor = -3<strong><br />输出:</strong> -2<strong><br />解释:</strong> 7/-3 = truncate(-2.33333..) = -2</pre><p>&nbsp;</p><p><strong>提示：</strong></p><ul>	<li>被除数和除数均为 32 位有符号整数。</li>	<li>除数不为&nbsp;0。</li>	<li>假设我们的环境只能存储 32 位有符号整数，其数值范围是 [&minus;2<sup>31</sup>,&nbsp; 2<sup>31&nbsp;</sup>&minus; 1]。本题中，如果除法结果溢出，则返回 2<sup>31&nbsp;</sup>&minus; 1。</li></ul>

## template

```python
import math
class Solution(object):
	def divide(self, dividend, divisor):
		if divisor == 0:
			return MAX_INT
		if dividend == 0:
			return 0
		isPositive = (dividend < 0) == (divisor < 0)
		m = abs(dividend)
		n = abs(divisor)
		res = math.log(m) - math.log(n)
		res = int(math.exp(res))
		if isPositive:
			return min(res, 2147483647)
		return max(0 - res, -2147483648)
if __name__ == '__main__':
	s = Solution()
	print(s.divide(1, 1))
```

## 答案

```python

```

## 选项

### A

```python

```

### B

```python

```

### C

```python

```