{
  "type": "code_options",
  "author": "csdn.net",
  "source": "solution.md",
  "exercise_id": "d75a74cf74a64aaba143a845e5fa74b8",
  "keywords": "算法初阶,排序和顺序统计量,中位数和顺序统计量",
  "title": "移动数组中的字符",
  "desc": [
    {
      "content": "\n在数组中有n个字符，使前面各字符顺序向后移动m个位置，并使最后m个字符变成最前面的 m 个字符",
      "language": "markdown"
    }
  ],
  "answer": [
    {
      "content": "",
      "language": "cpp"
    }
  ],
  "prepared": [
    [
      {
        "content": "",
        "language": "cpp"
      }
    ],
    [
      {
        "content": "",
        "language": "cpp"
      }
    ],
    [
      {
        "content": "",
        "language": "cpp"
      }
    ]
  ],
  "template": {
    "content": "#include <iostream>\nusing namespace std;\nvoid funShift(int m,char *p,int n)\n{\n\tchar c;\n\tfor (int j = 0; j < m;j++)\n\t{\n\t\tc = p[n-1];\n\t\tfor (int i = n-1;  i > 0; i--)\n\t\t{\n\t\t\tp[i] = p[i-1];\n\t\t}\n\t\tp[0] = c;\n\t}\n}\nint main() \n{ \n\tint i,m,n; \n\tcin >> m >> n; \n\tchar *p =new char[n+1];\n\tp[n] = 0;\n\tfor(i = 0; i < n; ++i) \n\t\tcin >> p[i]; \n\tfunShift(m,p,n); \n\tfor(i = 0; i < n; ++i) \n\t\tcout << p[i] << ' '; \n\tcout << endl; \n\tdelete [] p; \n\tgetchar();\n\tgetchar();\n\treturn 0;\n}",
    "language": "cpp"
  },
  "node_id": "dailycode-7077b339c1ef498ca92107cbc966a652",
  "license": "csdn.net",
  "created_at": 1637894158,
  "topic_link": "https://bbs.csdn.net/topics/600470169"
}