# 三数之和
给你一个包含 n
个整数的数组 nums
,判断 nums
中是否存在三个元素 a,b,c ,使得 a + b + c = 0 ?请你找出所有和为 0
且不重复的三元组。
注意:答案中不可以包含重复的三元组。
示例 1:
输入:nums = [-1,0,1,2,-1,-4]
输出:[[-1,-1,2],[-1,0,1]]
示例 2:
输入:nums = []
输出:[]
示例 3:
输入:nums = [0]
输出:[]
提示:
0 <= nums.length <= 3000
-105 <= nums[i] <= 105
以下错误的选项是?
## aop
### before
```cpp
#include
#include
#include
using namespace std;
```
### after
```cpp
int main()
{
Solution sol;
int arr[] = {-1,0,1,2,-1,-4};
int length1 = sizeof(arr) / sizeof(arr[0]);
vector nums(arr, arr + length1);
vector > res;
res = sol.threeSum(nums);
for (auto i : res)
{
for (auto j : i)
cout << j << ' ';
cout << endl;
}
return 0;
}
```
## 答案
```cpp
class Solution
{
public:
vector> threeSum(vector &nums)
{
sort(nums.begin(), nums.end());
int len = nums.size();
vector> ans;
if (nums.empty())
return {};
for (int i = 0; i < len; ++i)
{
if (i > 0 && nums[i] == nums[i - 1])
continue;
int newtar = -nums[i];
int low = i + 1;
int high = len - 1;
while (low < high)
{
if (nums[low] + nums[high] == newtar)
{
ans.push_back({nums[i], nums[low], nums[high]});
while (low < high && nums[low] == nums[low + 1])
++low;
while (low < high && nums[high] == nums[high - 1])
--high;
}
else
high--;
}
}
return ans;
}
};
```
## 选项
### A
```cpp
class Solution
{
public:
vector> threeSum(vector &nums)
{
sort(nums.begin(), nums.end());
if (nums.size() < 3 || nums.front() > 0 || nums.back() < 0)
return {};
vector> res;
for (int i = 0; i < nums.size(); i++)
{
int fix = nums[i];
if (fix > 0)
break;
if (i > 0 && fix == nums[i - 1])
continue;
int l = i + 1;
int r = nums.size() - 1;
while (l < r)
{
if (nums[l] + nums[r] == -fix)
{
if (l == i + 1 || r == nums.size() - 1)
{
res.push_back(vector{nums[i], nums[l], nums[r]});
l++;
r--;
}
else if (nums[l] == nums[l - 1])
l++;
else if (nums[r] == nums[r + 1])
r--;
else
{
res.push_back(vector{nums[i], nums[l], nums[r]});
l++;
r--;
}
}
else if (nums[l] + nums[r] < -fix)
l++;
else
r--;
}
}
return res;
}
};
```
### B
```cpp
class Solution
{
public:
static bool cmp(const int &a, const int &b)
{
return a < b;
}
vector> threeSum(vector &nums)
{
sort(nums.begin(), nums.end(), cmp);
vector::iterator it;
vector> res;
set> a;
for (int i = 0; i < nums.size(); i++)
{
if (nums[i] > 0)
break;
for (int j = i + 1; j < nums.size(); j++)
{
it = find(nums.begin() + j + 1, nums.end(), 0 - nums[i] - nums[j]);
if (it != nums.end())
{
vector temp;
temp.push_back(nums[i]);
temp.push_back(nums[j]);
temp.push_back(*it);
a.insert(temp);
}
}
}
for (auto k : a)
{
res.push_back(k);
}
return res;
}
};
```
### C
```cpp
class Solution
{
public:
vector > threeSum(vector &nums)
{
if (nums.size() < 3)
return {};
vector > res;
set > ret;
for (int i = 0; i < nums.size() - 2; i++)
{
for (int j = i + 1; j < nums.size() - 1; j++)
{
for (int k = j + 1; k < nums.size(); k++)
{
if (nums[i] + nums[k] + nums[j] == 0)
{
vector temp;
int a = (nums[i] < nums[j] ? nums[i] : nums[j]) < nums[k] ? (nums[i] < nums[j] ? nums[i] : nums[j]) : nums[k];
int b = (nums[i] > nums[j] ? nums[i] : nums[j]) > nums[k] ? (nums[i] > nums[j] ? nums[i] : nums[j]) : nums[k];
int c = 0 - a - b;
temp.push_back(a);
temp.push_back(c);
temp.push_back(b);
ret.insert(temp);
}
}
}
}
for (auto it : ret)
{
res.push_back(it);
}
return res;
}
};
```