# 文本左右对齐

给定一个单词数组和一个长度 maxWidth,重新排版单词,使其成为每行恰好有 maxWidth 个字符,且左右两端对齐的文本。

你应该使用“贪心算法”来放置给定的单词;也就是说,尽可能多地往每行中放置单词。必要时可用空格 ' ' 填充,使得每行恰好有 maxWidth 个字符。

要求尽可能均匀分配单词间的空格数量。如果某一行单词间的空格不能均匀分配,则左侧放置的空格数要多于右侧的空格数。

文本的最后一行应为左对齐,且单词之间不插入额外的空格。

说明:

示例:

输入:
    words = ["This", "is", "an", "example", "of", "text", "justification."]
    maxWidth = 16

输出:
[    "This    is    an",    "example  of text",    "justification.  " ]

示例 2:

输入:
    words = ["What","must","be","acknowledgment","shall","be"]
    maxWidth = 16

输出:
[   "What   must   be",   "acknowledgment  ",   "shall be        " ]
解释:
注意最后一行的格式应为 "shall be " 而不是 "shall be" 因为最后一行应为左对齐,而不是左右两端对齐,第二行同样为左对齐,这是因为这行只包含一个单词。

示例 3:

输入:
    words = ["Science","is","what","we","understand","well","enough","to","explain",
             "to","a","computer.","Art","is","everything","else","we","do"]
    maxWidth = 20

输出:
[   "Science  is  what we", "understand      well",   "enough to explain to",   "a  computer.  Art is",   "everything  else  we",   "do                  " ]

以下错误的选项是?

## aop ### before ```c #include using namespace std; ``` ### after ```c int main() { Solution sol; vector words = {"Science", "is", "what", "we", "understand", "well", "enough", "to", "explain", "to", "a", "computer.", "Art", "is", "everything", "else", "we", "do"}; int maxWidth = 20; vector res; res = sol.fullJustify(words, maxWidth); for (auto i : res) cout << i << " " << endl; return 0; } ``` ## 答案 ```c class Solution { public: vector fullJustify(vector &words, int maxWidth) { vector result; int wordsVecSize = words.size(); for (int beginIndex = 0; beginIndex < wordsVecSize;) { string tempRec = words[beginIndex]; int remainLength = maxWidth - words[beginIndex].size(); int cnt = 1; int endIndex = beginIndex + 1; while (endIndex < wordsVecSize) { int tempVaule = remainLength - words[endIndex].size(); if (tempVaule >= cnt) { remainLength = tempVaule; cnt += 1; ++endIndex; } else { break; } } if (cnt == 1) { tempRec = string(remainLength, ' '); } else if (endIndex != wordsVecSize) { vector spaceNum(cnt, remainLength / (cnt - 1)); remainLength %= (cnt - 1); for (int i = 1; i <= remainLength; ++i) { spaceNum[i] += 1; } for (int index = beginIndex + 1; index < endIndex; ++index) { tempRec += string(spaceNum[index - beginIndex], ' ') + words[index]; } } else { remainLength = maxWidth - words[beginIndex].size(); for (int index = beginIndex + 1; index < endIndex; ++index) { tempRec += " " + words[index]; remainLength = remainLength - 1 - words[index].size(); } tempRec += string(remainLength, ' '); } result.push_back(tempRec); beginIndex = endIndex; } return result; } }; ``` ## 选项 ### A ```c class Solution { public: vector fullJustify(vector &words, int maxWidth) { vector res; int i = 0; while (i < words.size()) { int residue_wid = 0; int begin = i; while (i < words.size() && residue_wid + words[i].size() <= maxWidth) { residue_wid += words[i].size() + 1; ++i; } if (i == words.size()) { res.push_back(packagestring(words, begin, i - 1, residue_wid - 1, maxWidth, false)); break; } res.push_back(packagestring(words, begin, i - 1, residue_wid - 1, maxWidth, true)); } return res; } string packagestring(vector &words, int starter, int ender, int strlen, int maxWidth, bool tail) { string res = ""; if (tail && starter < ender) { int cnt = ender - starter; int blk = (maxWidth - strlen) / cnt + 1; string spc = string(blk, ' '); int ofst = (maxWidth - strlen) % cnt; for (int i = starter; i < ender; ++i) { res += words[i] + spc; if (i - starter < ofst) res += ' '; } res += words[ender]; } else { string spc = string(maxWidth - strlen, ' '); for (int i = starter; i < ender; ++i) { res += words[i] + ' '; } res += words[ender] + spc; } return res; } }; ``` ### B ```c class Solution { public: vector fullJustify(vector &words, int L) { vector res; int i = 0; while (i < words.size()) { int j = i, len = 0; while (j < words.size() && len + words[j].size() + j - i <= L) { len += words[j++].size(); } string out; int space = L - len; for (int k = i; k < j; ++k) { out += words[k]; if (space > 0) { int tmp; if (j == words.size()) { if (j - k == 1) tmp = space; else tmp = 1; } else { if (j - k - 1 > 0) { if (space % (j - k - 1) == 0) tmp = space / (j - k - 1); else tmp = space / (j - k - 1) + 1; } else tmp = space; } out.append(tmp, ' '); space -= tmp; } } res.push_back(out); i = j; } return res; } }; ``` ### C ```c class Solution { public: vector fullJustify(vector &words, int maxWidth) { int n = words.size(), length, num = 0, i, j, k; string now; vector ans; for (i = 0; i < n;) { now.clear(); num = 0; length = words[i].length(); for (j = i; j < n - 1; j++) { if (words[j + 1].length() + length + num + 1 > maxWidth) break; num++; length += words[j + 1].length(); } if (j == n - 1) { for (k = i; k < n; k++) { now += words[k]; if (k != n - 1) now += " "; } for (k = 0; k < maxWidth - length - num; k++) now += " "; ans.push_back(now); } else { int black = maxWidth - length; if (num == 0) { now.append(words[i]); now.append(black, ' '); ans.push_back(now); } else { int x = black % num; int y = black / num; if (x == 0) { string kongge; for (k = 0; k < y; k++) kongge += " "; for (k = i; k <= j; k++) { now += words[k]; if (k != j) now += kongge; } ans.push_back(now); } else { string kongge; for (k = 0; k <= y; k++) kongge += " "; for (k = i; k <= j; k++) { now += words[k]; if (k != j) now += kongge; if (k - i + 1 == x) kongge.erase(kongge.begin()); } ans.push_back(now); } } } i = j + 1; } return ans; } }; ```