# 比酒量

有一群海盗（不多于20人），在船上比拼酒量。过程如下：打开一瓶酒，所有在场的人平分喝下，有几个人倒下了。再打开一瓶酒平分，又有倒下的，
再次重复...... 

直到开了第4瓶酒，坐着的已经所剩无几，海盗船长也在其中。当第4瓶酒平分喝下后，大家都倒下了。

等船长醒来，发现海盗船搁浅了。他在航海日志中写到：“......昨天，我正好喝了一瓶.......奉劝大家，开船不喝酒，喝酒别开船......”

请你根据这些信息，推断开始有多少人，每一轮喝下来还剩多少人。

如果有多个可能的答案，请列出所有答案，每个答案占一行。

格式是：人数,人数,...

例如,有一种可能是：```20,5,4,2,0```

以下错误的一项是？

## aop

### before

```cpp
#include <bits/stdc++.h>
using namespace std;
```
### after

```cpp

```

## 答案

```cpp
int d, a1[4];

int d1(int *a1)
{
    int sum = a1[0];
    for (int i = 1; i < 4; i++)
    {
        if (sum % a1[i] != 0)
            return i;
    }
    return 0;
}
int getS(int *a1)
{
    int sum = 0, ss = 1;
    while (d1(a1) != 0)
    {
        int index = d1(a1);
        a1[0] = a1[0] * a1[index];
        ss = a1[index];
        sum += ss;
    }
    return sum;
}

int main()
{
    for (int sum = 20; sum >= 1; sum--)
    {
        for (int a = 1; a <= 20; a++)
        {
            for (int b = 1; b <= 20; b++)
            {
                for (int c = 1; c <= 20; c++)
                {
                    a1[0] = sum, a1[1] = a, a1[2] = b, a1[3] = c;
                    if (getS(a1) == a1[0] && a > b && b > c && sum > a)
                    {
                        printf("%d, %d, %d, %d, 0\n", sum, a, b, c);
                    }
                }
            }
        }
    }
    return 0;
}
```
## 选项


### A

```cpp
int main()
{
    float n;
    float a, b, c;
    float s1, s2, s3;
    for (n = 5; n <= 20; n++)
    {
        for (a = 1; a <= n; a++)
            for (b = 1; b <= n; b++)
                for (c = 1; c <= n; c++)
                {
                    s1 = n - a;
                    s2 = n - a - b;
                    s3 = n - a - b - c;
                    if (1 / n + 1 / s1 + 1 / s2 + 1 / s3 == 1 && s1 > 0 && s2 > 0 && s3 > 0)
                        cout << n << "," << s1 << "," << s2 << "," << s3 << ","
                             << "0" << endl;
                }
    }
    return 0;
}
```

### B

```cpp
int cm(int a, int b)
{
    int temp;
    int mul;
    mul = a * b;
    if (a % b == 0)
        return a;
    else
    {
        while (a % b != 0)
        {
            temp = a % b;
            a = b;
            b = temp;
        }
        return mul * b;
    }
}
int main()
{
    int a, b, c, d;
    int temp;
    int ta, tb, tc, td;
    for (a = 20; a >= 5; a--)
        for (b = a - 1; b >= 4; b--)
            for (c = b - 1; c >= 3; c--)
                for (d = c - 1; d >= 2; d--)
                {
                    temp = cm(a, b);
                    temp = cm(temp, c);
                    temp = cm(temp, d);
                    ta = temp / a;
                    tb = temp / b;
                    tc = temp / c;
                    td = temp / d;
                    if (ta + tb + tc + td == temp)
                        cout << a << "," << b << "," << c << "," << d << ","
                             << "0" << endl;
                }
    return 0;
}
```

### C

```cpp
int main(void)
{
    float a, b, c, d;
    float x, y, z, m;
    for (x = 20; x >= 5; x--)
    {
        for (y = x - 1; y >= 4; y--)
        {
            for (z = y - 1; z >= 3; z--)
            {
                for (m = y - 1; m >= 2; m--)
                {
                    if (y * z * m + x * z * m + x * y * m + x * y * z == x * y * z * m)

                    {
                        cout << x << "," << y << "," << z << "," << m << ","
                             << "0" << endl;
                    }
                }
            }
        }
    }
}
```