# 最大单词长度乘积
给定一个字符串数组 words,找到 length(word[i]) * length(word[j]) 的最大值,并且这两个单词不含有公共字母。你可以认为每个单词只包含小写字母。如果不存在这样的两个单词,返回 0。
示例 1:
输入:["abcw","baz","foo","bar","xtfn","abcdef"]输出:16 解释: 这两个单词为"abcw", "xtfn"。
示例 2:
输入:["a","ab","abc","d","cd","bcd","abcd"]输出:4 解释:这两个单词为"ab", "cd"。
示例 3:
输入:["a","aa","aaa","aaaa"]输出:0 解释: 不存在这样的两个单词。
提示:
2 <= words.length <= 10001 <= words[i].length <= 1000words[i] 仅包含小写字母以下错误的选项是?
## aop ### before ```cpp ``` ### after ```cpp ``` ## 答案 ```cpp ``` ## 选项 ### A ```cpp ``` ### B ```cpp ``` ### C ```cpp ```