Skip to content
体验新版
项目
组织
正在加载...
登录
切换导航
打开侧边栏
机器未来
Paddle
提交
05eafcca
P
Paddle
项目概览
机器未来
/
Paddle
与 Fork 源项目一致
Fork自
PaddlePaddle / Paddle
通知
1
Star
1
Fork
0
代码
文件
提交
分支
Tags
贡献者
分支图
Diff
Issue
1
列表
看板
标记
里程碑
合并请求
0
Wiki
0
Wiki
分析
仓库
DevOps
项目成员
Pages
P
Paddle
项目概览
项目概览
详情
发布
仓库
仓库
文件
提交
分支
标签
贡献者
分支图
比较
Issue
1
Issue
1
列表
看板
标记
里程碑
合并请求
0
合并请求
0
Pages
分析
分析
仓库分析
DevOps
Wiki
0
Wiki
成员
成员
收起侧边栏
关闭侧边栏
动态
分支图
创建新Issue
提交
Issue看板
提交
05eafcca
编写于
7月 10, 2018
作者:
C
chenweihang
浏览文件
操作
浏览文件
下载
电子邮件补丁
差异文件
refine some messages and adjust data type
上级
8f2486ca
变更
1
显示空白变更内容
内联
并排
Showing
1 changed file
with
14 addition
and
15 deletion
+14
-15
paddle/fluid/operators/squeeze_op.cc
paddle/fluid/operators/squeeze_op.cc
+14
-15
未找到文件。
paddle/fluid/operators/squeeze_op.cc
浏览文件 @
05eafcca
...
...
@@ -30,13 +30,14 @@ class SqueezeOpInferShape : public framework::InferShapeBase {
const
auto
&
x_dims
=
ctx
->
GetInputDim
(
"X"
);
// Check input tensor dims (<6) Eigen limit.
PADDLE_ENFORCE
(
x_dims
.
size
()
<=
6
,
"Invalid dimnesions,
dynamic dimensions must have
"
"
between [1, 6] dimensions
(Eigen limit)."
);
"Invalid dimnesions,
the rank of Input(X)
"
"
should be in the range of [1, 6]
(Eigen limit)."
);
const
auto
&
axes
=
ctx
->
Attrs
().
Get
<
std
::
vector
<
int
>>
(
"axes"
);
for
(
int
a
:
axes
)
{
PADDLE_ENFORCE_LT
(
a
,
x_dims
.
size
(),
"The axis must be less than input tensor's rank."
);
"The squeeze axis should be less than input "
"tensor's rank."
);
}
auto
out_dims
=
GetOutputShape
(
axes
,
x_dims
);
...
...
@@ -50,30 +51,29 @@ class SqueezeOpInferShape : public framework::InferShapeBase {
static
framework
::
DDim
GetOutputShape
(
const
std
::
vector
<
int
>
squeeze_dims
,
const
framework
::
DDim
&
in_dims
)
{
int
num_squeeze_dims
=
static_cast
<
int
>
(
squeeze_dims
.
size
()
);
size_t
num_squeeze_dims
=
squeeze_dims
.
size
(
);
int
cnt_squeezed_dims
=
0
;
bool
should_squeeze
[
9
]
=
{
false
};
// Determines number of dimensions of output tensor after squeeze.
// Mark and count the dimensions need to be squeezed
if
(
num_squeeze_dims
==
0
)
{
for
(
int
idx
=
0
;
idx
<
static_cast
<
int
>
(
in_dims
.
size
()
);
++
idx
)
{
for
(
int
idx
=
0
;
idx
<
in_dims
.
size
(
);
++
idx
)
{
if
(
in_dims
[
idx
]
==
1
)
{
should_squeeze
[
idx
]
=
true
;
++
cnt_squeezed_dims
;
}
}
}
else
{
for
(
in
t
idx
=
0
;
idx
<
num_squeeze_dims
;
++
idx
)
{
for
(
size_
t
idx
=
0
;
idx
<
num_squeeze_dims
;
++
idx
)
{
int
current
=
squeeze_dims
[
idx
]
<
0
?
squeeze_dims
[
idx
]
+
in_dims
.
size
()
:
squeeze_dims
[
idx
];
// Check current index.
// Check current index
, the upper limit has beed checked in line 36
.
PADDLE_ENFORCE
(
current
>=
0
,
"Invalid axis, negative axis is out of range."
);
// PADDLE_ENFORCE_LT(current, in_dims.size(), "Invalid axis is given.");
PADDLE_ENFORCE
(
in_dims
[
current
]
==
1
,
"Invalid axis index, the axis will be squeezed should be 1."
);
"Invalid axis, the negative axis is out of range."
);
PADDLE_ENFORCE
(
in_dims
[
current
]
==
1
,
"Invalid axis index, the axis that will be squeezed "
"should equal 1."
);
if
(
!
(
should_squeeze
[
current
]))
{
++
cnt_squeezed_dims
;
...
...
@@ -84,8 +84,7 @@ class SqueezeOpInferShape : public framework::InferShapeBase {
// Make output dimensions
std
::
vector
<
int64_t
>
output_shape
(
in_dims
.
size
()
-
cnt_squeezed_dims
,
0
);
for
(
int
in_idx
=
0
,
out_idx
=
0
;
in_idx
<
static_cast
<
int
>
(
in_dims
.
size
());
++
in_idx
)
{
for
(
int
in_idx
=
0
,
out_idx
=
0
;
in_idx
<
in_dims
.
size
();
++
in_idx
)
{
if
(
!
should_squeeze
[
in_idx
])
{
output_shape
[
out_idx
++
]
=
in_dims
[
in_idx
];
}
...
...
@@ -123,7 +122,7 @@ class SqueezeOpMaker : public framework::OpProtoAndCheckerMaker {
AddInput
(
"X"
,
"(Tensor). The input tensor of squeeze operator."
);
AddOutput
(
"Out"
,
"(Tensor). The output tensor of squeeze operator."
);
AddAttr
<
std
::
vector
<
int
>>
(
"axes"
,
"(std::vector<int>). List of
positive
integers,"
"(std::vector<int>). List of integers,"
" indicate the dimensions to squeeze."
)
.
SetDefault
({});
AddAttr
<
bool
>
(
"inplace"
,
...
...
编辑
预览
Markdown
is supported
0%
请重试
或
添加新附件
.
添加附件
取消
You are about to add
0
people
to the discussion. Proceed with caution.
先完成此消息的编辑!
取消
想要评论请
注册
或
登录